12xb=468,hỏi b=.........
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a: \(\Leftrightarrow\left\{{}\begin{matrix}x+1=2x\\y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1\\y=1\end{matrix}\right.\)
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a) \(x^3-x^2-12x=x\left(x^2-x-12\right)=x\left(x-4\right)\left(x+3\right)\)
b) \(x^2+7x=x\left(x+7\right)\)
\(a,=x\left(x^2-x-12\right)=x\left(x^2-4x+3x-12\right)\\ =x\left(x-4\right)\left(x+3\right)\\ b,=x\left(x+7\right)\)
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\(A=468+15\times468+85\times468\\ =468\times\left(1+15+85\right)\\ =468\times101\\ =47268\)
Em xem lại đề câu này không thể tính nhanh được.
\(A=468+15x468+85x468\\ A=468x\left(15+85+1\right)\\ A=468x101\\ A=47268\)
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a) 468 + 379 = 847
379 + 468 = 847
b) 6509 + 2876 = 9385
2876 + 6509= 9385
c) 4268 + 76 = 4344
76 + 4268 =4344
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Bài 1:
b: \(=\left(x-2y\right)\left(x+2y\right)+4\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-2y+4\right)\)
c: \(=\left(x+y-3\right)\left(x+y+3\right)\)
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Bài 1:
a: \(3xy^2-12x=3x\left(y^2-4\right)=3x\left(y-2\right)\left(y+2\right)\)
b: \(x^2-4y^2+4x+8y\)
\(=\left(x-2y\right)\left(x+2y\right)+4\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-2y+4\right)\)
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a) \(\dfrac{4}{6}+\dfrac{7}{13}+\dfrac{17}{9}-\dfrac{8}{9}+\dfrac{14}{6}+\dfrac{19}{13}\)
\(=\dfrac{2}{3}+\dfrac{7}{13}+\dfrac{17}{9}-\dfrac{8}{9}+\dfrac{7}{3}+\dfrac{19}{13}\)
\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)+\left(\dfrac{17}{9}-\dfrac{8}{9}\right)\)
\(=\dfrac{9}{3}+\dfrac{26}{13}+\dfrac{9}{9}\)
\(=3+2+1\)
\(=6\)
b) \(\dfrac{328}{435}\times\dfrac{468}{432}\times\dfrac{435}{164}\times\dfrac{432}{984}\times\dfrac{164}{468}\)
\(=\dfrac{328\times468\times435\times432\times164}{435\times432\times164\times984\times468}\)
\(=\dfrac{328}{984}\)
\(=\dfrac{1}{3}\)
b=39
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