X+6:(-8)=20
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\(a,x+21=6\\ \Rightarrow x=-15\\ b,x-10=-8\\ \Rightarrow x=2\\ c,\left(-8\right)x=\left(-7\right)\left(-6\right)\\ \Rightarrow\left(-8\right)x=42\\ \Rightarrow x=-4\\ d,20+8\left(x+3\right)=5^2.4\\ \Rightarrow20+8\left(x+3\right)=25.4\\ \Rightarrow20+8\left(x+3\right)=100\\ \Rightarrow8\left(x+3\right)=80\\ \Rightarrow x+3=10\\ \Rightarrow x=7\)
\(a.x+21=6\\ x=6-21\\ x=-15\\ b.x-10=-8\\ x=-8+10\\ x=2\\ c.-8x=-7.\left(-6\right)-2\\ -8x=42-2\\ -8x=40\\ x=40:\left(-8\right)\\ x=-5\)
\(d.20+8\left(x+3\right)=5^2.4\\ 20+8x+24=25.4\\ 44+8x=100\\ 8x=100-44\\ 8x=56\\ x=56:8\\ x=7\)
\(8x-48+4x-12-14=-x+4\)
\(\Leftrightarrow12x-75=-x+4\Leftrightarrow13x=79\Leftrightarrow x=\dfrac{79}{13}\)
\(-7\left(8-x\right)-6\left(x+9\right)=20-x\Leftrightarrow-56+7x-6x-54=20-x\)
\(\Leftrightarrow2x=130\Leftrightarrow x=65\)
\(9x-63-80+60x=-7x+15\Leftrightarrow76x=158\Leftrightarrow x=\dfrac{79}{38}\)
\(-96-16x-60+30x=-40x-16\Leftrightarrow54x=140\Leftrightarrow x=\dfrac{70}{27}\)
\(17x-102-14x-28=4x-24-2x+4\Leftrightarrow x=110\)
\(x\)\(\times\)( \(x\) + 1) = 2 + 4 + 6 + 8 + 10 + 20
\(x\) \(\times\)(\(x\) + 1) = 50
\(x\) \(\times\)(\(x+1\)) = 2 \(\times\) 5 \(\times\) 5
Nếu \(x\) là số tự nhiên thì không tồn tại
Nếu \(x\) là số thực thì câu hỏi này không phù hợp lớp 5 em nhá
a: x-4/5=3/7
=>x=3/7+4/5=43/35
b: x+3/7=4/5
=>x=4/5-3/7=13/35
c: 19/20-x=8/5-3/4
=>19/20-x=32/20-15/20=17/20
=>x=2/20=1/10
d: =>4/5*x=2/21
=>x=2/21:4/5=5/42
e: =>x:7/9=6/8
=>x=6/8*7/9=3/4*7/9=21/36=7/12
f: =>x/6=2/3-1/3=1/3
=>x=2
a: x-4/5=3/7
=>x=3/7+4/5=43/35
b: x+3/7=4/5
=>x=4/5-3/7=13/35
c: 19/20-x=8/5-3/4
=>19/20-x=32/20-15/20=17/20
=>x=2/20=1/10
d: =>4/5*x=11/21
=>x=55/84
e: =>x=6/8*7/9=42/72=7/12
f: =>x/6=2/3-1/3=1/3
=>x=2
\(\frac{7.x}{8}-5.\left(x-9\right)=20.x+\frac{1,5}{6}\)
\(\Leftrightarrow7.x-5.\left(x-9\right)=20x.8+\frac{1,5}{6}.8\)
\(\Leftrightarrow7.x-40\left(x-9\right)=160x+2\)
\(\Leftrightarrow7x-40+360=160x+2\)
\(\Leftrightarrow-33x+360=160x+2\)
\(\Leftrightarrow-33x=160x+x-360\)
\(\Leftrightarrow-33x=160x-358\)
\(\Leftrightarrow-33x-160x=160x-358\)
\(\Leftrightarrow-193x=-358\)
\(\Rightarrow x=\frac{358}{193}\)
1) 20-(x+2)=8
\(x+2=20-8\)
\(x+2=12\)
\(x=12-2\)
\(x=10\)
2) (x-4)-6=18
\(x-4=18+6\)
\(x-4=24\)
\(x=24+4\)
\(x=28\)
1) \(20-\left(x+2\right)=8\)
<=>\(x+2=20-8\)
<=>\(x+2=12\)
<=>\(x=12-2\)
<=>\(x=10\)
vậy x=10
2) \(\left(x-4\right)-6=18\)
<=>\(x-4=18-6\)
<=>\(x-4=12\)
<=>\(x=12+4\)
<=>\(x=16\)
vậy x = 16
\(\)
a,x-(20-3x)=x+7
=>x-20+3x=x+7
=>x-20+3x-x=7
=>x+3x-x=7+20
=>3x=27
=>x=27:3
=>x=9
`x + 6 : (-8) = 20`
`x - 0,75 = 20`
`x = 20 + 0,75`
`x = 20,75`
Vậy: `x = 20,75`
\(x+6\) : (-8) = 20
\(x\) - 0,75 = 20
\(x\) = 20 + 0,75
\(x\) = 20,75
Vậy \(x\) = 20,75