70+5x=100
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DT
3
20 tháng 3 2016
(5x-1)3-2=70
<=>(5x-1).3=70+2=72
<=>5x-1=72:3
<=>5x-1=24
<=>5x=24+1=25
<=>5x=25:5=5
CB
3
KV
28 tháng 7 2023
a) \(56,78\times13,45-13,45\times47,48+13,45\)
\(=13,45\times\left(56,78-47,78+1\right)\)
\(=13,45\times10\)
\(=134,5\)
b) Em ghi đề lại cho rõ ràng
c) \(\left(100+101+102+...+999+1000\right)\times\left(320-160:\dfrac{1}{2}\right)\)
\(=\left(100+101+102+...+999+1000\right)\times\left(320-320\right)\)
\(=\left(100+101+102+...+999+1000\right)\times0\)
\(=0\)
d) \(3,4\times\left(16,35-7,35\right)+0,125\times3,4\times8\)
\(=3,4\times9+3,4\times1\)
\(=3,4\times\left(9+1\right)\)
\(=3,4\times10\)
\(=34\)
e) \(1,2\times21,3+1,2\times27,7+49\times0,8\)
\(=1,2\times\left(21,3+27,7\right)+49\times0,8\)
\(=1,2\times49+49\times0,8\)
\(=49\times\left(1,2+0,8\right)\)
\(=49\times2\)
\(=98\)
f) \(23,24\times5,8-23,24\times4,7-15,24-8\)
\(=23,24\times\left(5,8-4,7\right)-23,24\)
\(=23,24\times1,1-23,24\)
\(=23,24\times\left(1,1-1\right)\)
\(=23,24\times0,1\)
\(=2,324\)
H9
HT.Phong (9A5)
CTVHS
1 tháng 11 2023
a) \(A=\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{100}}\)
\(2A=2\cdot\left(\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{100}}\right)\)
\(2A=1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{101}}\)
\(2A-A=1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{99}}-\dfrac{1}{2}-\dfrac{1}{2^2}-...-\dfrac{1}{2^{100}}\)
\(A=1-\dfrac{1}{2^{100}}\)
b) \(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{2023\cdot2024}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{2023}-\dfrac{1}{2024}\)
\(=1-\dfrac{1}{2024}\)
\(=\dfrac{2024}{2024}-\dfrac{1}{2024}\)
\(=\dfrac{2023}{2024}\)
13 tháng 8 2018
\(a,\left(x-5\right).\frac{30}{100}=\frac{200x}{100}+5\)
\(\left(x-5\right).\frac{3}{10}=2x+5\)
\(\frac{3x}{10}-\frac{3}{2}=2x+5\)
\(\frac{3}{10}x-2x=\frac{3}{2}+5\)
\(x\left(\frac{3}{10}-2\right)=\frac{13}{2}\)
\(x.\frac{-17}{10}=\frac{13}{2}\)
\(x=\frac{13}{2}:\frac{-17}{10}\)
\(x=\frac{13}{2}\cdot\frac{-10}{17}\)
\(x=\frac{-65}{17}\)
Vậy \(x=\frac{-65}{17}\)
Bài 2:
Ta có:\(\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}=\frac{-5}{21}\left(x+y+z\right)\)
Mà đề bài cho \(x+y=-z\Rightarrow\frac{-5}{21}\left(-z+z\right)=\frac{-5}{21}.0=0\Rightarrow A=0\)
Vậy \(A=0\)
5x=100-70
5x=30
x=30:5
x=6
Vậy x=6
`70 + 5x =100`
`=> 5x = 100 - 70`
`=> 5x = 30`
`=> x = 30 :5`
`=> x = 6`
Vậy `x =6`