nhập vào số nguyên n, in ra sô chính phương từ 1 đến n có tổng các chữ số là số lẻ (pascal)
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uses crt;
var n,i,d,dem,kt,t,kt1,t1,t2,t3,max,min,x,j:integer;
a,b:array[1..100]of integer;
st:string;
begin
clrscr;
write('Nhap n='); readln(n);
str(n,st);
d:=length(st);
for i:=1 to d do
val(st[i],a[i],x);
dem:=1;
b[1]:=a[1];
for i:=1 to d do
begin
kt:=0;
for j:=1 to dem do
if a[i]=b[j] then kt:=1;
if kt=0 then
begin
inc(dem);
b[dem]:=a[i];
end;
end;
writeln('Cac chu so cua ',n,' la: ');
for i:=1 to dem do
write(b[i]:4);
writeln;
t:=0;
for i:=1 to d do
t:=t+a[i];
writeln('Tong cac chu so cua ',n,' la: ',t);
kt1:=0;
for i:=2 to trunc(sqrt(t)) do
if t mod i=0 then
begin
kt1:=1;
break;
end;
if (kt1=0) and (t>1) then writeln(t,' la so nguyen to')
else writeln(t,' khong la so nguyen to');
writeln('Cac chu so o vi tri le cua ',n,' la: ');
t1:=0;
for i:=1 to d do
if i mod 2=1 then
begin
write(a[i]:4);
t1:=t1+a[i];
end;
writeln;
writeln('Tong cac chu so o vi tri le la: ',t1);
if trunc(sqrt(t1))=sqrt(t1) then writeln(t1,' la so chinh phuong')
else writeln(t1,' khong la so chinh phuong');
writeln('Cac chu so o vi tri chan cua ',n,' la: ');
t2:=0;
for i:=1 to d do
if i mod 2=0 then
begin
write(a[i]:4);
t2:=t2+a[i];
end;
writeln('Tong cac chu so o vi tri chan la: ',t2);
t3:=0;
for i:=1 to t2 do
if t2 mod i=0 then t3:=t3+i;
if (t3=t2) and (t2>0) then writeln(t2,' la so hoan hao')
else writeln(t2,' khong la so hoan hao');
max:=a[1];
min:=a[1];
for i:=1 to d do
begin
if max<a[i] then max:=a[i];
if min>a[i] then min:=a[i];
end;
writeln('Chu so lon nhat cua ',n,' la: ',max);
writeln('Chu so nho nhat cua ',n,' la: ',min);
writeln('Tong cua chung la: ',max+min);
readln;
end.
uses crt;
var n,i,t:integer;
begin
clrscr;
readln(n);
for i:=2 to n do
if i mod 2=1 then write(i:4);
writeln;
t:=0;
for i:=1 to n do
if i mod 2=0 then t:=t+i;
writeln(t);
readln;
end.
a)
uses crt;
var i,n:integer;
begin
clrscr;
repeat
write('Nhap n='); readln(n);
until n<100;
if n mod 2=0 then
begin
for i:=0 to n do
if i mod 2=0 then write(i:4);
end
else writeln(n,' khong la so chan');
readln;
end.
b)
uses crt;
var i,n:integer;
begin
clrscr;
repeat
write('Nhap n='); readln(n);
until n<100;
if n mod 2=1 then
begin
for i:=1 to n do
if i mod 2=1 then write(i:4);
end
else writeln(n,' khong la so le');
readln;
end.
Bài 2:
uses crt;
var x,i,n,dem:integer;
begin
clrscr;
readln(n);
dem:=0;
for i:=1 to n do
begin
readln(x);
if x mod 2=0 then inc(dem);
end;
writeln(dem);
readln;
end.
program so_le;
uses crt;
var
n,i,d:integer;
a:Array[1..32000] of integer;
begin
clrscr;
write('nhap n: ');
readln(n);
for i:= 1 to n do
begin
write('nhap a[',i,']: ');
readln(a[i]);
end;
d:=0;
for i:= 1 to n do
if a[i] mod 2 <> 0 then d:=d+1;
write('so luong so nguyen la so le la: ',d);
readln;
end.
Câu 58:
Var n:integer;
Begin
Write('n = ');readln(n);
If n mod 2 <> 0 then write(n,' la so le')
Else write(n,' khong la so le');
Readln
End.
Câu 61:
Var n:integer;
Begin
Write('n = ');readln(n);
If n mod 2 = 0 then write(n,' la so chan')
Else write(n,' khong la so chan');
Readln
End.
uses crt;
var n,i,kt,j,t:integer;
begin
clrscr;
write('Nhap n='); readln(n);
writeln('Cac so nguyen to trong khoang tu 2 toi ',n,' la: ');
for i:=2 to n do
begin
kt:=0;
for j:=2 to i-1 do
if i mod j=0 then kt:=1;
if kt=0 then write(i:4);
end;
writeln;
writeln('Cac so chinh phuong trong khoang tu 0 toi ',n,' la: ');
for i:=0 to n do
if trunc(sqrt(i))=sqrt(i) then write(i:4);
writeln;
writeln('Cac so hoan hao trong khoang tu 1 toi ',n,' la: ');
for i:=1 to n do
begin
t:=0;
for j:=1 to i-1 do
if i mod j=0 then t:=t+j;
if t=i then write(i:4);
end;
readln;
end.
Câu 1:
Program HOC24;
var i,p: integer;
t: longint;
begin
write('Nhap P: '); readln(p);
t:=0;
for i:=1 to p do if i mod 2<>0 then t:=t+i;
write('Tong cac so le la: ',t);
readln
end.
bạn tham khảo nhé
uses crt;
var i,n:longint;
function cp(n:longint):boolean;
var i:longint;
begin
for i:=1 to n do if i*i=n then break;
if i<n then cp:=true else cp:=false;
end;
function tl(n:longint):boolean;
var i,tong:longint;
begin
tong:=0;
while n<>0 do
begin
tong:=tong+n mod 10;
n:=n div 10;
end;
if tong mod 2=1 then tl:=true else tl:=false;
end;
begin
readln(n);
for i:=1 to n do if (cp(i)=true) and (tl(i)=true) then writeln(i);
readln
end.