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65.(35−9)−35.(65+9)=
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PT
1
CM
21 tháng 11 2018
Đáp án là C
Ta có:
(-65) - (x + 35) + 101 = -65 - x - 35 + 101
= -65 - 35 + 101 - x = -(65 + 35) + 101 - x
= -100 + 101 - x = (101 - 100) - x = 1 - x
VV
1
S
3
TH
27 tháng 7 2016
Ta có:
\(\frac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\frac{2^{35}.\left(9.5\right)^{25}.13^{22}.\left(5.7\right)^{16}}{9^{26}.\left(5.13\right)^{22}.\left(7.4\right)^{17}.\left(5.5\right)^9}\)
\(=\frac{2^{35}.9^{25}.5^{25}.13^{22}.5^{16}.7^{16}}{9^{26}.13^{22}.5^{22}.7^{17}.4^{17}.5^9.5^9}\)
\(=\frac{2^{35}.5^3}{9.4^{17}.5^2.7}\)
\(=\frac{2^{35}.5}{9.4^{17}.7}\)
\(=\frac{2^{35}.5}{9.2^{34}.7}\)
\(=\frac{2.5}{9.7}\)
\(=\frac{10}{63}\)
p/s: - Ko chắc ~
25 tháng 3 2020
a) Ta có: \(\left(-65\right)\cdot\left(87-17\right)-87\cdot\left(17-65\right)\)
\(=-65\cdot87+65\cdot17-87\cdot17+87\cdot65\)
\(=17\left(65-87\right)=17\cdot\left(-22\right)=-374\)
b) Ta có: \(\left(135-35\right)\cdot\left(-37\right)+37\cdot\left(-42-58\right)\)
\(=\left(-100\right)\cdot37+37\cdot\left(-100\right)\)
\(=37\left(-100-100\right)=37\cdot\left(-200\right)=-7400\)
TD
1
19 tháng 11 2017
\(A=\dfrac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\dfrac{2^{35}.3^{50}.5^{25}.13^{22}.5^{16}.7^{16}}{3^{52}.13^{22}.5^{22}.2^{34}.7^{17}.5^{18}}\)
\(=\dfrac{2.5^3}{3^2.5^2.7}=\dfrac{2.5}{3^2.7}=\dfrac{10}{63}\)
NB
4
30 tháng 12 2018
\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\cdot\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\\ =\left(\dfrac{1}{4}+\dfrac{7}{20}+\dfrac{13}{20}+\dfrac{3}{4}\right)\cdot\left(\dfrac{5}{3}+\dfrac{13}{3}\right)\\ =\left[\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\left(\dfrac{7}{20}+\dfrac{13}{20}\right)\right]\cdot\left(\dfrac{18}{3}\right)\\ =\left(\dfrac{4}{4}+\dfrac{20}{20}\right)\cdot6\\ =\left(1+1\right)\cdot6\\ =2\cdot6\\ =12\)
VH
30 tháng 12 2018
\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\)
\(=\left(\dfrac{1}{4}+\dfrac{7}{20}+\dfrac{13}{20}+\dfrac{3}{4}\right)\left(\dfrac{5}{3}+\dfrac{13}{3}\right)\)
\(=\left\{\left[\dfrac{1}{4}+\dfrac{3}{4}\right]+\left[\dfrac{7}{20}+\dfrac{13}{20}\right]\right\}\left(\dfrac{5+13}{3}\right)\)
=\(\left(1+1\right).6=2.6=12\)
30 tháng 9 2021
2 . 53 . 27 + 6 . 9 . 87 - 3 . 18 . 40
= 2. 53 . 9 . 3 + 2. 3 .9 .87 - 3 .2 .9 .40
= 54.53+54.87-54.40
=54(53+87-40)
=54. 100=5400
12 . 25 + 29 . 25 + 59 . 25
= 25 . ( 12+29+59)
=25 . 90
=2250
43 . 37 + 93 . 43 + 57 . 61 + 69 . 57
= 43.(37+93)+57(61+69)
=43.130+57.130
=130.(43+57)
=130.100
=13 000
12 . 53 + 53 . 172 - 53
=53(12+172-1)
=53.184
=9752
35 . 54 + 35 . 58 + 65 . 75 + 65 . 45
=35(54+58)+65(75+45)
=35.112+65.120
=3920+7800
=11720
39 . 8 + 70 . 3 + 31 . 8
=8(39+31)+70.3
=8.70+70.3
=70.(8+3)
=70.11
=770
NT
3 tháng 10 2017
Bài 35 :
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(A=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)
\(A=\frac{2^8.2^2.98}{2^8.104}\)
\(A=\frac{2^8.4.98}{2^8.4.26}\)
\(A=\frac{49}{13}\)
Vậy \(A=\frac{49}{13}\)
\(B=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{11.3^{29}-9^{15}}{2^2.\left(3^{14}\right)^2}\)
\(B=\frac{11.3^{29}-9^{15}}{2^2.3^{28}}\)
\(B=\frac{11.3^{29}-\left(3^2\right)^{15}}{4.3^{28}}\)
\(B=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(B=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(B=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)
\(B=\frac{3^{29}.8}{4.3^{28}}\)
\(B=\frac{3^{28}.3.4.2}{4.3^{28}}\)
\(B=3.2\)
\(B=6\)
Vậy B = 6
BD
3 tháng 10 2017
A = 2^10 . 13 + 2^10 . 65 / 2^8 . 104
= 2^10 ( 13 + 65 ) / 2^8 . 104 = 2^10 . 78 / 2^8 . 104 = 2^8 . 2^2 . 78 / 2^8 . 104 = 2^8 . 4 . 78 / 2^8 . 104 = 2^8 . 312 / 2^8 . 104
= 312/104
= 3
B = 11 . 3^22 . 3^7 - 9^15 / ( 2.3^14)^2
= 11 . 3^29 - (3^2)^15 / ( 3.2^14)^2
= 11 . 3^29 - 3^30 / ( 3. 2 )^28
= ( 8 + 3 ) . 3^29 - 3^30 / ( 3. 2)^28
= 8 . 3^29 + 3.3^29 - 3^30 / ( 3.2)^28
= 8 . 3^29 + 3^30 - 3^30 / ( 3 . 2)^28
= 8 . 3^29 / 3^28 . 2^28
= 2^3 . 3 / 2^28
= 3/ 2^25
Ta có: \(65\cdot\left(35-9\right)-35\left(65+9\right)\)
\(=65\cdot35-65\cdot9-65\cdot35-35\cdot9\)
\(=-65\cdot9-35\cdot9\)
\(=-9\left(65+35\right)=-9\cdot100=-900\)