a ) 24 * y - 3 * 5 * y = 52 - 24
b ) 32 * y + 22 * y = 26 * 22 - 13
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a) 23.25 + 75.23 - 1300
= 23.(25 + 75) - 1300
= 23.100 - 1300
= 2300 - 1300
= 1000
b) 36 : 3² - 5.2²
= 36 : 9 - 5.4
= 4 - 20
= -16
c) 183 + 80 : [20 - 4.(5² - 24)]
= 183 + 80 : [20 - 4.(25 - 24)]
= 183 + 80 : (20 - 4.1)
= 183 + 80 : 16
= 183 + 5
= 188
d) (-125) - [148 + 5.(-25)]
= -125 - (148 - 125)
= -125 - 148 + 125
= (-125 + 125) - 148
= 0 - 148
= -148
a) 23.25 + 75.23 - 1300
= 23. (25+75) - 1300
= 23.100 - 1300
= 2300 - 1300 = 1000
b) 36 : 32 - 5 . 22
= 36: 9 - 5.4
= 4 - 20 = -16
c) 183 + 80 : [ 20 - 4 ( 52 - 24 ) ]
= 183 + 80: [20 - 4.(25-24)]
= 183 + 80 : [20 - 4.1)]
= 183 + 80: [20 - 4]
= 183 + 80:16
= 183 + 5 = 188
d) (-125) - [148 + 5 . (-25) ]
= -125 - 148 + 125
= (125 - 125) - 148
= 0 - 148 = -148
1) Ta có: \(\left(x+2\right)^2+\left(x-3\right)^2\)
\(=x^2+4x+4+x^2-6x+9\)
\(=2x^2-2x+13\)
2) Ta có: \(\left(4-x\right)^2-\left(x-3\right)^2\)
\(=\left(4-x-x+3\right)\left(4-x+x-3\right)\)
\(=-2x+7\)
3) Ta có: \(\left(x-5\right)\left(x+5\right)-\left(x+5\right)^2\)
\(=x^2-25-x^2-10x-25\)
=-10x-50
4) Ta có: \(\left(x-3\right)^2-\left(x-4\right)\left(x+4\right)\)
\(=x^2-6x+9-x^2+16\)
=-6x+25
5) Ta có: \(\left(y^2-6y+9\right)-\left(y-3\right)^2\)
\(=y^2-6y+9-y^2+6y-9\)
=0
6) Ta có: \(\left(2x+3\right)^2-\left(2x-3\right)\left(2x+3\right)\)
\(=4x^2+12x+9-4x^2+9\)
=12x+18
a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
\(1,=-\left(y^2+12y+36\right)=-y^2-12y-36\)
\(2,=-\left(16-8y+y^2\right)=-16+8y-y^2\)
\(3,=-\left(\dfrac{4}{9}+\dfrac{4}{3}x+x^2\right)=-\dfrac{4}{9}-\dfrac{4}{3}x-x^2\)
\(4,=-\left(x^2-3x+\dfrac{9}{4}\right)=-x^2+3x-\dfrac{9}{4}\)
\(5,-\left(2+3y\right)^2=-\left(4+12y+9y^2\right)=-4-12y-9y^2\)
.... mấy ý còn lại bn tự lm nhé, tương tự thhooi
1) \(-\left(y+6\right)^2=-y^2-12y-36\)
2) \(-\left(4-y\right)^2=-y^2+8y-16\)
3) \(-\left(x+\dfrac{2}{3}\right)^2=-x^2-\dfrac{4}{3}x-\dfrac{4}{9}\)
4) \(-\left(x-\dfrac{3}{2}\right)^2=-x^2+3x-\dfrac{9}{4}\)
5) \(-\left(3y+2\right)^2=-9y^2-12y-4\)
6) \(-\left(2y-3\right)^2=-4y^2+12y-9\)
7) \(-\left(5x+2y\right)^2=-25x^2-20xy-4y^2\)
8) \(-\left(2x-\dfrac{3}{2}\right)^2=-4x^2+6x-\dfrac{9}{4}\)