3 mũ 4 . 9
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Bài 1:
a) 02002 < 02023
b) 20220 = 20230
c) 549 < 5510
d) ( 4 + 5 )3 > 42 + 52
đ) 92 - 32 > ( 9 - 3 )2
Bài 2:
a) 32 x 43 - 32 + 333
= 9 x 64 - 9 + 333
= 576 - 9 + 333
= 567 + 333
= 900
b) 5 x 43 + 24 x 5 + 410
= 5 x 64 + 24 x 5 + 1
= 5 x ( 64 + 24 ) + 1
= 5 x 88 + 1
= 440 + 1
= 441
c) 23 x 42 + 32 x 5 - 40 x 12023
= 8 x 16 + 9 x 5 - 40 x 1
= 128 + 45 - 40
= 133
Bài 1 :
a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)
b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)
c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)
d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)
đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)
a) \(12^{10}:3^{10}=\left(12:3\right)^{10}=4^{10}\)
b) \(4^5.3^{10}=4^5.3^{2.5}=4^5.\left(3^2\right)^5=4^5.9^5=\left(4.9\right)^5=36^5\)
c) \(9^{10}:27^4=\left(3^2\right)^{10}:\left(3^3\right)^4=3^{2.10}:3^{3.4}=3^{20}:3^{12}=3^8\)
d) \(15^8:9^4=15^8:\left(3^2\right)^4=15^8:3^8=\left(15:3\right)^8=5^8\)
\(4^2\cdot120-4^3\cdot17+4^2\cdot34\)
\(=4^2\left(120-4\cdot17+34\right)\)
\(=16\left(120-68+34\right)\)
\(=16\cdot86=1088\)
\(\left(\dfrac{9}{4}\right)^3.\left(\dfrac{12}{9}\right)^0:\left(-\dfrac{9}{8}\right)^3=\left(\dfrac{9}{4}\right)^3.1:\left(-\dfrac{9}{8}\right)^3\)
\(=\left(\dfrac{9}{4}:\dfrac{-9}{8}\right)^3=\left(-2\right)^3=-8\)
$\begin{array}{c} \color{#db8}{\texttt{Cre: Capybara}} \end{array}$
`3^4 . 9 = 3^4 . 3^2 = 3^(4+2)=3^6`
\(3^4.9\)
\(=>81.9\)
\(=>729\)