Tìm các số tự nhiên biết:
a) \(2^{n-1}:2=256\)
b) \(5^n+5^{n-2}=650\)
c) \(2^{n-3}+2^{n+1}=136\)
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a)
\(2^{n-1}:2=256\)
\(\Rightarrow2^{n-1}:2=2^8\)
\(\Rightarrow2^{n-1}=2^9\)
\(\Rightarrow n-1=9\)
\(\Rightarrow n=10\)
b)
\(5^n+5^{n-2}=650\)
\(\Rightarrow5^n+5^n:5^2=650\)
\(\Rightarrow5^n+5^n:25=650\)
\(\Rightarrow5^n+5^n.\dfrac{1}{25}=650\)
\(\Rightarrow5^n.\left(1+\dfrac{1}{25}\right)=650\)
\(\Rightarrow5^n.\dfrac{26}{25}=650\)
\(\Rightarrow5^n=625\)
\(\Rightarrow5^n=5^4\)
\(\Rightarrow n=4\)
c)
\(2^{n-3}+2^{n+1}=136\)
\(\Rightarrow2^n.\dfrac{1}{2^3}+2^n.2=136\)
\(\Rightarrow2^n.\left(\dfrac{1}{8}+2\right)=136\)
\(\Rightarrow2^n.\dfrac{17}{8}=136\)
\(\Rightarrow2^n=64\)
\(\Rightarrow2^n=2^6\)
\(\Rightarrow n=6\)
a.
\(5^n+5^{n+2}=650\)
\(5^n\left(1+5^2\right)=650\)
\(5^n\left(1+25\right)=650\)
\(5^n\cdot26=650\)
\(5^n=650:26\)
\(5^n=25\)
\(5^n=5^2\Rightarrow n=2\)
b.
\(3^{n+3}+5\cdot3^n=864\)
\(3^n\left(3^3+5\right)=864\)
\(3^n\left(27+5\right)=864\)
\(3^n\cdot32=864\)
\(3^n=864:32\)
\(3^n=27\)
\(3^n=3^3\Rightarrow n=3\)
a) 5n + 5n+2 = 650
=> 5n + 5n . 52 = 650
=> 5n (1 + 52) = 650
=> 5n . 26 = 650
=> 5n = 25
=> n = 2
b) 3n+ 3 + 5.3n = 864
=> 3n . 33 + 5.3n = 864
=> 3n(33 + 5) = 864
=> 3n . 32 = 864
=> 3n = 27
=> n = 3
a,
5n + 5n + 2 = 650
=> 5n + 5n.52 = 650
=> 5n(1 + 52) = 650
=> 5n.26 = 650
=> 5n = 25
=> n = 2
a) 5n +5n+2 = 650
5n + 5n.52 = 650
5n.(1+25 ) = 650
5n.26= 650
5n = 25 = 52
=> n = 2
b) 3n+3 +5.3n = 864
3n.33 +5.3n = 864
3n.(33+5) = 864
3n.32 = 864
3n = 27 = 33
=> n = 3
các bài cn lại bn dựa vào mak lm nha!
a) 5n + 5n+2 = 650
=> 5n+5n+2=54 +52
=> n+n+2 = 4+2
=>2n +2 = 6
=> n=2
b) 3n + 5.3n= 864
=> 3n .(1+5) = 864
=> 3n = 864 :6
=> 3n =144
=> 3n =32+33+34-3
=> n=2+3+4-3=6
c ) 5n+3 - 5n+1= (125)4 . 120
=> 5n+3 - 5n+ = 512. ( 5^3 -5)
=> n+3 -n = 12.2
=> 3=14 ( vô lí )
=> không tồn tại n
Kunzy Nguyễn: Mik ko có ý chê bạn đâu nhưng mà câu a mik thấy bạn giải có chút gọi là ''sai''!
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
2n-1:2=256
2n-1=512=29=>n-1=9=>n=10
5n+5n-2=650
5n-2(25+1)=650=>5n-2=25=52
=>n-2=2=>n=4
a) \(2^{n-1}:2=256\)
\(2^{n-1-1}=256\)
\(2^{n-2}=2^8\)
\(\Rightarrow n-2=8\)
\(\Rightarrow n=10\)
vay \(n=10\)