tìm x
a)\(45⋮x\)
b)\(x⋮12\)
c)\(219-7.\left(x+1\right)=100\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, 219 - 7.(x + 1) = 100
7.(x + 1) = 219 - 100
7.(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
a, 219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119/7
x+1=17
x=17-1
x=16
Vậy x=16
b, 20+23(x+3)=52.4
20+8(x+3)=100
8(x+3)=100-20
8(x+3)=80
x+3=80/8
x+3=10
x=10-3
x=7
Vậy x=7
219 - 7 ( x + 1 ) = 100
7 ( x + 1 ) = 219 - 100
7 ( x + 1 ) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 16
a) 219 - 7(x + 1) = 100 <=> 7(x+1) = 219 - 100
<=> 7(x+1) = 119 <=> x + 1 = 119 : 7 <=> x + 1 = 17
a) 219−7(x+1)=100
- 7(x+ 1)= 100 - 219
- 7(x+ 1)= - 119
x+1 = -119 : (-7)
x+1 = 17
x= 17-1
x= 16
b) (3x - 6). 3 = 34
(3x - 6). 3 = 81
(3x - 6)= 81: 3
(3x - 6)= 27
3x= 27+ 6
3x= 33
x= 33:3
x= 11
b) (3x−6).3=34
b) \(3^x\cdot3^2+3^x=7290\)
\(3^x\left(3^2+1\right)=720\)
\(3^x\cdot10=7290\)
\(=>3^x=729=3^6\)
=> \(x=6\)
\(a,\Leftrightarrow\dfrac{9}{5}=-\dfrac{3}{20}-x\\ \Leftrightarrow-\dfrac{9}{5}=x+\dfrac{3}{20}\\ \Leftrightarrow x=-\dfrac{9}{5}-\dfrac{3}{20}=-\dfrac{39}{20}\\ b,\Leftrightarrow-x+2x=\dfrac{3}{5}+\dfrac{4}{7}\\ \Leftrightarrow x=\dfrac{41}{35}\\ c,\Leftrightarrow\dfrac{3}{8}-\dfrac{1}{5}+\dfrac{5}{8}-x=\dfrac{1}{5}\\ \Leftrightarrow1-x=\dfrac{2}{5}\\ \Leftrightarrow x=1-\dfrac{2}{5}=\dfrac{3}{5}\)
\(x+5=20-\left(12-17\right)\)
\(x+5=20-\left(-5\right)\)
\(x+5=20+5\)
\(x=5\)
a, \(219-7\left(X+1\right)=100\)
\(\Rightarrow219-7X-7=100\)
\(\Rightarrow7X=219-7-100=112\)
\(\Rightarrow X=112:7=16\)
b,\(\left(3X-6\right)x3=3^4\)
\(\Rightarrow3X-6=81:3=27\)
\(\Rightarrow3X=27+6=33\)
\(\Rightarrow X=33:3=11\)
c,\(3636:\left(12X-91\right)=36\)
\(\Rightarrow12X-91=3636:36=101\)
\(\Rightarrow12X=101+91=192\)
\(\Rightarrow X=192:12=16\)
Đúng luôn nên...hằng ngày k cho mk 3 lần, bao h đủ 100 lần thì tui nhé
a, 45 chia hết cho x
=> x thuộc Ư(45)
=> x thuộc {1;45;3;15;5;9}
vậy...
b, x chia hết cho 12
=> x thuộc B(12)
=> x thuộc {0;12;24;36;48;60;...}
vậy.....
c, 219-7.(x+1)=100
7.(x+1)=219-100
7.(x+1)=119
x+1 = 17
x = 17-1
x = 16 vậy...
a, 45 \(⋮\)x \(\Rightarrow\)x\(\in\)Ư ( 45 ) = { \(\pm\)1;\(\pm\)3;\(\pm\)5;\(\pm\)9;\(\pm\)15;\(\pm\)45}
b, \(x⋮12\Rightarrow x\in B\left(12\right)=\left\{0;12;24;36;48....\right\}\)
\(c,219-7\left(x+1\right)=100\)
\(\Rightarrow7\left(x+1\right)=219-100\)
\(\Rightarrow7\left(x+1\right)=119\)
\(\Rightarrow x+1=119:7\)
\(\Rightarrow x+1=17\)
\(\Rightarrow x=16\)