Tìm x :
a) 3^x = 81
b) 3^x + 1/2 - 1/4 = 9,25
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a) (x-9,25.4) : (x-9,25.4) = 1
=> x-9,5.4 = x-9,25.4 = 1
=> x-9,25.4 = 1
x-9,25 = 1:4
x-9,25 = 0,25
x = 0,25 + 9,25
x = 9,5
b) 42-36:[2.(2.x+1)+4] = 40
36:[2.(2.x+1)+4] = 42 - 40
36:[2.(2.x+1)+4] = 2
2.(2.x+1)+4 = 36 : 2
2.(2.x+1)+4 = 18
2.(2x+1) = 18 - 4
2.(2x+1) = 14
2x+1 = 14 : 2
2x+1 = 7
2x = 7 - 1
2x = 6
x = 6 : 2
x = 3
a, \(x=\dfrac{3}{4}-1=\dfrac{3}{4}-\dfrac{4}{4}=-\dfrac{1}{4}\)
b, \(x=\dfrac{1}{5}-4=\dfrac{1}{5}-\dfrac{20}{5}=-\dfrac{19}{5}\)
c, \(x=2+\dfrac{1}{5}=\dfrac{10}{5}+\dfrac{1}{5}=\dfrac{11}{5}\)
d, \(x=\dfrac{1}{81}-\dfrac{5}{3}=\dfrac{1}{81}-\dfrac{135}{81}=-\dfrac{134}{81}\)
a)\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\)
\(\Leftrightarrow\frac{3^5}{5^5}\times x=\frac{3^7}{7^7}\)
\(\Leftrightarrow x=\frac{3^7}{7^7}:\frac{3^5}{5^5}\)
\(\Leftrightarrow x=\frac{3^7\times5^5}{7^7\times3^5}\)
\(\Leftrightarrow x=\frac{3^2\times5^5}{7^7}\)
b)\(\left(\frac{-1}{3}\right)^3\times x=\frac{1}{81}\)
\(\Leftrightarrow\frac{\left(-1\right)^3}{3^3}\times x=\frac{1}{3^4}\)
\(\Leftrightarrow x=\frac{1}{3^4}:\frac{-1}{3^3}\)
\(\Leftrightarrow x=\frac{1\times3^3}{3^4\times\left(-1\right)}\)
\(\Leftrightarrow x=\frac{1}{-3}\)
c)\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)
\(\Leftrightarrow x=\frac{5}{6}\)
d)\(\Leftrightarrow\left(x+\frac{1}{2}\right)^4=\left(\frac{2}{3}\right)^4\)
\(\Leftrightarrow x+\frac{1}{2}=\frac{2}{3}\)
\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{6}\)
\(\left(x+4\right)^2-81=0\Leftrightarrow\left(x+4\right)^2-9^2=0\)
\(\Leftrightarrow\left(x+4+9\right)\times\left(x+4-9\right)=0\)
\(\Leftrightarrow\left(x+13\right)\times\left(x-5\right)=0\)
\(\left[{}\begin{matrix}x+13=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-13\\x=5\end{matrix}\right.\)
a) 3/4 - x = 1 c) x - 1/5 = 2
x = 3/4 - 1 x = 2 + 1/5
x = -1/4 x = 11/5
Vậy x = -1/4 Vậy x = 11/5
b) x+4 = 1/5 d) x + 5/3 = 1/81
x = 1/5 -4 x = 1/81 -5/3
x = -19/5 x = -134/81
Vậy x = -19/5
a) 3/4 - x = 1
\(x=\frac{3}{4}-1\)
\(x=\frac{-1}{4}\)
b) x + 4 = 1/5
\(x=\frac{1}{5}-4\)
\(x=\frac{-19}{5}\)
c) x - 1/5 = 2
\(x=2+\frac{1}{5}\)
\(x=\frac{11}{5}\)
d) x + 5/3 = 1/81
\(x=\frac{1}{81}-\frac{5}{3}\)
\(x=\frac{-134}{81}\)
chúc bạn học tốt
\(3^x=81\)
\(3^x=3^4\)
\(x=4\)
b.
\(3^x+\dfrac{1}{2}-\dfrac{1}{4}=9,25\)
\(3^x+0,5-0,25=9,25\)
\(3^x=9,25+0,25-0,5\)
\(3^x=9\)
\(3^x=3^2\)
\(x=2\)
a) \(3^x=81\)
\(3^x=3^4\)
\(x=4\)
b) \(3^x+\dfrac{1}{2}-\dfrac{1}{4}=9,25\)
\(3^x+\dfrac{1}{4}=9+\dfrac{1}{4}\)
\(3^x=3^2\)
\(x=2\)