25 x 2³ + 12 - 2² x 5² x 2
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Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 12 2023
a, (-25) + 276 - (276 - 25)
= (-25) + 276 - 276 + 25
= [ (-25) + 25] - (276 - 276)
= 0 - 0
= 0
b, 24 x 46 + 24 x 53 + 24
= 24 x ( 46 + 53 + 1)
= 24 x 100
= 2400
CM
19 tháng 11 2018
a. 4 x 126 x 25
= (4 x 25) x 126
= 100 x 126
= 12600
b. (9 x 8 – 12 – 5 x 12) x ( 1 + 2 + 3 + 4 + 5)
= (72 – 12 – 60) x ( 1 + 2 + 3 + 4 + 5)
= 0 x ( 1 + 2 + 3 + 4 + 5)
= 0
23 tháng 7 2023
a) 4.25-12.5+170:10
=100-60+17
=40+17
=57
b) (7+33:32).4-3
=(7+3).4-3
=10.4-3
=40-3
=37
c) 12:{400:[500-(125+25.7)]}
=12:{400:[500-(125+175)]}
=12:{400:[500-300]}
=12:{400:200}
=12:2
=6
d) 168+{[2.(24+32)-2560]:72}
=168+{[2.(16+9)-1]:49}
=168+{[2.25-1]:49}
=168+{[50-1]:49}
=168+{49:49}
=168+1
=169
7 tháng 7 2023
Bài 1
a) \(5\times72\times10\times2=\left(5\times2\times10\right)\times72=100\times72=7200\)
b) \(40\times125=5\times\left(8\times125\right)=5\times1000=5000\)
c) \(16\times6\times25=4\times4\times6\times25=\left(4\times6\right)\times\left(4\times25\right)=24\times100=2400\) Bài 2:
a) \(24\times57+43\times24=24\times\left(57+43\right)=24\times100=2400\)
b) \(12\times19+80\times12+12=12\times\left(19+80+1\right)=12\times100=1200\)
c) \(\left(36\times15\times169\right)\div\left(5\times18\times13\right)\)
\(=\left(18\times2\times3\times5\times13\times13\right)\div\left(5\times18\times13\right)\)
\(=\left(2\times3\times13\right)\times\left(18\times5\times13\right)\div\left(5\times18\times13\right)\)
\(=2\times3\times13\)
\(=78\)
d) \(\left(44\times52\times60\right)\div\left(11\times13\times15\right)\)
\(=\left(4\times11\times4\times13\times4\times15\right)\div\left(11\times13\times15\right)\)
\(=\left(4\times4\times4\right)\times\left(11\times13\times15\right)\div\left(11\times13\times15\right)\)
\(=4\times4\times4\)
\(=64\)
Bài 3:
a) \(x-280\div35=5\times54\)
\(x-8=270\)
\(x=270+8\)
\(x=278\)
b) \(\left(x-280\right)\div35=54\div4\)
\(\left(x-280\right)\div35=\dfrac{27}{2}\)
\(x-280=\dfrac{27}{2}\times35\)
\(x-280=\dfrac{945}{2}\)
\(x=\dfrac{945}{2}+280\)
\(x=\dfrac{1505}{2}\)
c) \(\left(x-128+20\right)\div192=0\)
\(x-128+20=0\times192\)
\(x-128+20=0\)
\(x-128=0-20\)
\(x-128=-20\)
\(x=-20+128\)
\(x=108\)
d) \(4\times\left(x+200\right)=460+85\times4\)
\(4\times\left(x+200\right)=460+340\)
\(4\times\left(x+200\right)=800\)
\(x+200=800\div4\)
\(x+200=200\)
\(x=200-200\)
\(x=0\)
Bài 4:
a) \(\dfrac{7}{12}-\dfrac{5}{12}=\dfrac{2}{12}=\dfrac{1}{6}\)
b) \(\dfrac{8}{11}+\dfrac{19}{11}=\dfrac{27}{11}\)
c) \(\dfrac{3}{8}+\dfrac{5}{12}=\dfrac{9}{24}+\dfrac{10}{24}=\dfrac{19}{24}\)
d) \(\dfrac{3}{4}+\dfrac{7}{12}=\dfrac{9}{12}+\dfrac{7}{12}=\dfrac{16}{12}=\dfrac{4}{3}\)
Bài 5:
a) \(x-\dfrac{6}{7}=\dfrac{5}{2}\)
\(x=\dfrac{5}{2}+\dfrac{6}{7}\)
\(x=\dfrac{47}{14}\)
b) \(\dfrac{12}{7}\div x+\dfrac{2}{3}=\dfrac{7}{5}\)
\(\dfrac{12}{7}\div x=\dfrac{7}{5}-\dfrac{2}{3}\)
\(\dfrac{12}{7}\div x=\dfrac{11}{15}\)
\(x=\dfrac{12}{7}\div\dfrac{11}{15}\)
\(x=\dfrac{180}{77}\)
25 tháng 6 2023
1:
=>2x-3=0 hoặc 5/2-x=0
=>x=3/2 hoặc x=5/2
2: =>x=1/2+12=12,5
3: =>(2x+3/5-3/5)(2x+3/5+3/5)=0
=>2x(2x+6/5)=0
=>x=0 hoặc x=-3/5
4: =>-1/6x=-1/3
=>x=1/3:1/6=2
5: =>1/4:x=1/4
=>x=1
6: =>2/5x+11/15=1
=>2/5x=4/15
=>x=2/3
HP
21 tháng 9 2021
a. \(x-\dfrac{2}{35}=\dfrac{-2}{25}\)
<=> \(x=\dfrac{-2}{25}+\dfrac{2}{35}\)
<=> x = \(-\dfrac{4}{175}\)
b. \(\dfrac{11}{12}-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{3}\)
<=> \(\dfrac{11}{12}-x-\dfrac{2}{5}=\dfrac{2}{3}\)
<=> \(-x=\dfrac{2}{3}-\dfrac{11}{12}+\dfrac{2}{5}\)
<=> \(-x=\dfrac{3}{20}\)
<=> \(x=\dfrac{-3}{20}\)
c. \(\dfrac{2}{5}+\dfrac{1}{4}x=\dfrac{-3}{10}\)
<=> \(\dfrac{1}{4}x=\dfrac{-3}{10}-\dfrac{2}{5}\)
<=> \(\dfrac{1}{4}x=\dfrac{-7}{10}\)
<=> \(x=\dfrac{-14}{5}\)
21 tháng 9 2021
a) \(x-\dfrac{2}{35}=-\dfrac{2}{25}\)
\(\Rightarrow x=-\dfrac{2}{25}+\dfrac{2}{35}\)
\(\Rightarrow x=-\dfrac{4}{175}\)
b) \(\dfrac{11}{12}-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{3}\)
\(\Rightarrow x+\dfrac{2}{5}=\dfrac{11}{12}-\dfrac{2}{3}\)
\(\Rightarrow x+\dfrac{2}{5}=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{1}{4}-\dfrac{2}{5}\)
\(\Rightarrow x=-\dfrac{3}{20}\)
c) \(\dfrac{2}{5}+\dfrac{1}{4}x=-\dfrac{3}{10}\)
\(\Rightarrow\dfrac{1}{4}x=-\dfrac{3}{10}-\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{4}x=-\dfrac{7}{10}\)
\(\Rightarrow x=-\dfrac{7}{10}:\dfrac{1}{4}\)
\(\Rightarrow x=-\dfrac{14}{5}\)
\(25\cdot2^3+12-2^2\cdot5^2\cdot2\\ =25\cdot8+12-4\cdot25\cdot2\\ =200+12-200\\ =\left(200-200\right)+12\\ =12\)
25 x 23 + 12 - 22 x 52 x 2
= 25 x 8 + 12 - 4 x 25 x 2
= 200 + 12 - 100 x 2
= 200 + 12 - 200
= (200 - 200) + 12
= 0 + 12
= 12