(4/3)^1-2x=(-8/27)^4
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
27 tháng 10 2021
a: x=3
b: \(2x-1=2\)
hay \(x=\dfrac{3}{2}\)
c: \(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
NH
2
22 tháng 7 2016
a) \(3,8:\left(2x\right)=\frac{1}{4}:\frac{8}{3}\)
\(=3,8:\left(2x\right)=\frac{3}{32}\)
\(\Rightarrow2x=3,8:\frac{3}{32}=\frac{608}{15}\)
\(\Rightarrow x=\frac{608}{15}:2=\frac{304}{15}\)
b) Yêu cầu j vậy pn?
22 tháng 7 2016
\(3,8:\left(2x\right)=\frac{1}{4}:\frac{8}{3}\)
\(\Rightarrow2x=\frac{608}{15}\)
\(\Rightarrow x=\frac{304}{15}\)
VN
Võ Ngọc Phương
VIP
1 tháng 10 2023
\(\left(3-x\right)^3=-\dfrac{27}{64}\)
\(\left(3-x\right)^3=\left(\dfrac{-3}{4}\right)^3\)
\(=>3-x=\dfrac{-3}{4}\)
\(x=3-\dfrac{-3}{4}=\dfrac{12}{4}+\dfrac{3}{4}\)
\(x=\dfrac{15}{4}\)
________
\(\left(x-5\right)^3=\dfrac{1}{-27}\)
\(\left(x-5\right)^3=\left(\dfrac{-1}{3}\right)^3\)
\(=>x-5=\dfrac{-1}{3}\)
\(x=\dfrac{-1}{3}+5=\dfrac{-1}{3}+\dfrac{15}{3}\)
\(x=\dfrac{14}{3}\)
_____________
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8}\)
\(\left(x-\dfrac{1}{2}\right)^3=\left(\dfrac{3}{2}\right)^3\)
\(=>x-\dfrac{1}{2}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}+\dfrac{1}{2}\)
\(x=2\)
________
\(\left(2x-1\right)^2=\dfrac{1}{4}\)
\(\left(2x-1\right)^2=\left(\dfrac{1}{2}\right)^2\) hoặc \(\left(2x-1\right)^2=\left(\dfrac{-1}{2}\right)^2\)
\(=>2x-1=\dfrac{1}{2}\) \(2x-1=\dfrac{-1}{2}\)
\(2x=\dfrac{1}{2}+1=\dfrac{1}{2}+\dfrac{2}{2}\) \(2x=\dfrac{-1}{2}+1=\dfrac{-1}{2}+\dfrac{2}{2}\)
\(2x=\dfrac{3}{2}\) \(2x=\dfrac{1}{2}\)
\(x=\dfrac{3}{2}:2=\dfrac{3}{2}.\dfrac{1}{2}\) \(x=\dfrac{1}{2}:2=\dfrac{1}{2}.\dfrac{1}{2}\)
\(x=\dfrac{3}{4}\) \(x=\dfrac{1}{4}\)
____________
\(\left(2-3x\right)^2=\dfrac{9}{4}\)
\(\left(2-3x\right)^2=\left(\dfrac{3}{2}\right)^2\) hoặc \(\left(2-3x\right)^2=\left(\dfrac{-3}{2}\right)^2\)
\(=>2-3x=\dfrac{3}{2}\) \(2-3x=\dfrac{-3}{2}\)
\(3x=2-\dfrac{3}{2}=\dfrac{4}{2}-\dfrac{3}{2}\) \(3x=2-\dfrac{-3}{2}=\dfrac{4}{2}+\dfrac{3}{2}\)
\(3x=\dfrac{1}{2}\) \(3x=\dfrac{7}{2}\)
\(x=\dfrac{1}{2}.\dfrac{1}{3}\) \(x=\dfrac{7}{2}.\dfrac{1}{3}\)
\(x=\dfrac{1}{6}\) \(x=\dfrac{7}{6}\)
______________
\(\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\) -> Kiểm tra đề câu này
1 tháng 10 2023
(3-x)3=(-\(\dfrac{3}{4}\))3
3-x=-\(\dfrac{3}{4}\)
x=3-(-\(\dfrac{3}{4}\))
x=\(\dfrac{15}{4}\)
25 tháng 3 2021
a) Ta có: \(\dfrac{-3}{5}x+\dfrac{-7}{4}=\dfrac{3}{10}\)
\(\Leftrightarrow\dfrac{-3}{5}x=\dfrac{3}{10}+\dfrac{7}{4}=\dfrac{41}{20}\)
\(\Leftrightarrow x=\dfrac{41}{20}:\dfrac{-3}{5}=\dfrac{41}{20}\cdot\dfrac{-5}{3}\)
hay \(x=-\dfrac{41}{12}\)
Vậy: \(x=-\dfrac{41}{12}\)
LN
3
10 tháng 7 2017
\(\left(x-2,5\right)^2=\frac{4}{9}\)
\(\left(x-2,5\right)^2=\left(\frac{2}{3}\right)^2\)
\(x-2,5=\frac{2}{3}\)
\(x=\frac{2}{3}+2,5\)
\(x=\frac{19}{6}\)
\(\left(2x+\frac{1}{3}\right)^3=\frac{-8}{27}\)
\(\left(2x+\frac{1}{3}\right)^3=\left(\frac{-2}{3}\right)^3\)
\(2x+\frac{1}{3}=\frac{-2}{3}\)
\(2x=\frac{-2}{3}-\frac{1}{3}\)
\(2x=-1\)
\(x=\frac{-1}{2}\)
LD
10 tháng 7 2017
\(\left(x-2,5\right)^2=\left(\frac{2}{3}\right)^2\)
\(\Rightarrow\)\(\orbr{\begin{cases}x-2,5=\frac{2}{3}\\x-2,5=-\frac{2}{3}\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x=\frac{2}{3}+\frac{5}{2}\\x=-\frac{2}{3}+\frac{5}{2}\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x=\frac{4}{6}+\frac{15}{6}=\frac{19}{6}\\x=-\frac{4}{6}+\frac{15}{6}=\frac{11}{6}\end{cases}}\)
VV
7 tháng 1 2022
\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
Đề có sai không ạ?
\(\left(\dfrac{4}{3}\right)^{1-2x}=\left(-\dfrac{8}{27}\right)^4\)
=>\(\left(\dfrac{2^2}{3}\right)^{1-2x}=\left(\dfrac{8}{27}\right)^4=\left(\dfrac{2}{3}\right)^{12}\)
=>\(1-2x=log_{\dfrac{4}{3}}\left(\dfrac{2}{3}\right)^{12}\)
=>\(2x=1-log_{\dfrac{4}{3}}\left(\dfrac{2}{3}\right)^{12}\)
=>\(x=\dfrac{1}{2}-\dfrac{1}{2}\cdot log_{\dfrac{4}{3}}\left(\dfrac{2}{3}\right)^{12}\)