Bài 1 : Tìm X , biết
a) 25 - (5-x)= -7 d) ( 2x + 1) .(x- \(\dfrac{1}{7}\)) = 0
b) \(\dfrac{1}{2}\)+ \(\dfrac{2}{3}\):(x-1) = \(\dfrac{3}{4}\)
c) \(\dfrac{3}{7}\)+\(\dfrac{4}{7}\)x = \(\dfrac{1}{3}\) giúp mình với
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Bài 1 : Tìm X , biết
a) 25 - (5-x)= -7 d) ( 2x + 1) .(x- \(\dfrac{1}{7}\)) = 0
b) \(\dfrac{1}{2}\)+ \(\dfrac{2}{3}\):(x-1) = \(\dfrac{3}{4}\)
c) \(\dfrac{3}{7}\)+\(\dfrac{4}{7}\)x = \(\dfrac{1}{3}\) giúp mình với
a: 25-(5-x)=-7
=>5-x=25+7=32
=>x=5-32=-27
b: \(\dfrac{1}{2}+\dfrac{2}{3}:\left(x-1\right)=\dfrac{3}{4}\)
=>\(\dfrac{2}{3}:\left(x-1\right)=\dfrac{3}{4}-\dfrac{1}{2}=\dfrac{1}{4}\)
=>\(x-1=\dfrac{2}{3}:\dfrac{1}{4}=\dfrac{2}{3}\cdot4=\dfrac{8}{3}\)
=>\(x=\dfrac{8}{3}+1=\dfrac{11}{3}\)
d: \(\left(2x+1\right)\left(x-\dfrac{1}{7}\right)=0\)
=>\(\left[{}\begin{matrix}2x+1=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{7}\end{matrix}\right.\)
c: \(\dfrac{3}{7}+\dfrac{4}{7}x=\dfrac{1}{3}\)
=>\(\dfrac{4}{7}x=\dfrac{1}{3}-\dfrac{3}{7}=\dfrac{7}{21}-\dfrac{9}{21}=-\dfrac{2}{21}\)
=>\(x=-\dfrac{2}{21}:\dfrac{4}{7}=-\dfrac{2}{21}\cdot\dfrac{7}{4}=\dfrac{-1}{6}\)