Tìm x :
a) (3.x-2)3=2.32
b) 5x+1-5x=500
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\(\left(5x-1\right)^2-\left(5x-4\right)\left(5x+4\right)=7\)
\(25x^2-10x+1-25x^2+16=7\)
\(17-10x=7\)
\(10x=10\)
\(x=1\)
a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)
b, \(-2x+2=2\Leftrightarrow x=0\)
c, \(-2x-6=-8\Leftrightarrow x=1\)
ta có
a. (5x-7)(x-9)-(-x+3)(-5x+2)= 2x(x-4)-(x-1)(2x+3)
\(\Leftrightarrow5x^2-52x+63-\left(5x^2-17x+6\right)=2x^2-8x-\left(2x^2+x-3\right)\)
\(\Leftrightarrow-35x+57=-9x+3\Leftrightarrow26x=54\Leftrightarrow x=\frac{27}{13}\)
b. (x-3)(-x+10)+(x-8)(x+3)= (5x^2-1)(x+3)-5x^3-15x^2
\(\Leftrightarrow-x^2+13x-30+x^2-5x-24=5x^3+15x^2-x-3-5x^3-15x^2\)
\(\Leftrightarrow8x-54=-x-3\Leftrightarrow9x=51\Leftrightarrow x=\frac{17}{3}\)
a) (x-2)^3-x(x+1)(x-1)+6x(x-3)=0
\(x^3-6x^2+12x-8-x\left(x^2-1\right)+6x\left(x-3\right)=0\)
\(x^3-6x^2+12x-8-x^3+x+6x^2-18x=0\)
\(-5x-8=0\)
\(x=-\frac{8}{5}\)
Mai mik làm mấy bài kia sau
a) (5x+1)2-(5x+3).(5x-3)=30
\(\Leftrightarrow25x^2+10x+1-25x^2+9-30=0\)
\(\Leftrightarrow10x-20=0\)
\(\Leftrightarrow10x=20\)
\(\Leftrightarrow x=2\)
b) (x-3).(x2+3x+9)+x.(x+2).(2-x)=1
\(\Leftrightarrow x^3-3^3+x\left(4-x^2\right)-1=0\)
\(\Leftrightarrow x^3-27+4x-x^3-1=0\)
\(\Leftrightarrow4x-28=0\)
\(\Leftrightarrow4x=28\)
\(\Leftrightarrow x=7\)
a)\(\left(5x-1\right)^2-\left(5x-4\right)\left(5x+4\right)=7\)
\(\Leftrightarrow25x^2-10x+1-25x^2+16=7\)
\(\Leftrightarrow-10x=-10\)
\(\Leftrightarrow x=1\)
b) k hiểu đề
1. a) \(( 5x-1)^2 - (5x-4) ( 5x+4) = 7\)
\(\Leftrightarrow\)\(25x^2-10x+1-(25x^2-16)=7\)
\(\Leftrightarrow\)\(25x^2-10x+1-25x^2+16-7=0\)
\(\Leftrightarrow\)\(10x=10\)
\(\Rightarrow x=1\)
b) \(( 4x-1)^2 - (2x+3)^2 + 5(x+2)^2 + 3(x-2) ( x+2) = 500\)
\(\Leftrightarrow\)\(16x^2-8x+1-4x^2-12x-9+5x+10+3x^2-12=500\)
\(\Leftrightarrow\)\(15x^2-15x=510\)
\(\Leftrightarrow\)\(15(x^2-x)=510\)
\(\Leftrightarrow\)\(x^2-x=34\)
\(\Rightarrow x=-5,352349955\)
c) \((x-2)^3 - (x-2) ( x^2+2x+4 ) + 6(x-2)(x+2) = 60\)
\(\Leftrightarrow x^3-6x^2+12x-8-\left(x^3-2^3\right)+6\left(x^2-4\right)=60\)
\(\Leftrightarrow x^3-6x^2+12x-8-x^3+8+6x^2-24=60\)
\(\Leftrightarrow12x-24=60\)
\(\Leftrightarrow12x=84\)
\(\Rightarrow x=7\)
a) (3.x - 2)3 = 2.32
=> (3.x - 2)3 = 64 = 43
=> 3.x - 2 = 4
=> 3.x = 6
=> x = 2.
b) 5x+1 - 5x = 500
=>5x.5 - 5x = 500
=> 5x.(5 - 1) = 500
=> 5x.4 = 500
=> 5x = 125 = 53
=> x = 3
\(a,\left(3.x-2\right)^3=2.32\)
\(\Rightarrow\left(3x-2\right)^3=64\)
\(\Rightarrow\left(3x-2\right)^3=4^3\)
\(\Rightarrow3x-2=4\)
\(\Rightarrow3x=4+2=6\)
\(\Rightarrow x=2\)
\(b,5^{x+1}-5^x=500\)
\(\Rightarrow5^x.5-5^x=500\)
\(\Rightarrow5^x\left(5-1\right)=500\)
\(\Rightarrow5^x=500:4=125=5^3\)
\(\Rightarrow x=3\)