Question

[Lê Thành Nhật]

Answer 1

[Nguyễn Lê Phước Thịnh]

Bài 18:

a: \(\left(-\dfrac{40}{51}\cdot0,32\cdot\dfrac{17}{20}\right):\dfrac{64}{75}\)

\(=-\dfrac{40}{20}\cdot\dfrac{17}{51}\cdot\dfrac{8}{25}\cdot\dfrac{75}{64}\)

\(=-\dfrac{2}{3}\cdot\dfrac{8}{64}\cdot\dfrac{75}{25}=-\dfrac{2}{3}\cdot3\cdot\dfrac{1}{8}=-\dfrac{2}{8}=-\dfrac{1}{4}\)

b: \(-\dfrac{10}{11}\cdot\dfrac{8}{9}+\dfrac{7}{18}\cdot\dfrac{10}{11}=\dfrac{10}{11}\left(-\dfrac{8}{9}+\dfrac{7}{18}\right)\)

\(=\dfrac{10}{11}\left(-\dfrac{16}{18}+\dfrac{7}{18}\right)=\dfrac{10}{11}\cdot\dfrac{-9}{18}=\dfrac{10}{11}\cdot\dfrac{-1}{2}=-\dfrac{5}{11}\)

c: \(\dfrac{3}{14}:\dfrac{1}{28}-\dfrac{13}{21}:\dfrac{1}{28}+\dfrac{29}{42}:\dfrac{1}{28}-8\)

\(=\left(\dfrac{3}{14}-\dfrac{13}{21}+\dfrac{29}{42}\right):\dfrac{1}{28}-8\)

\(=\left(\dfrac{9}{42}-\dfrac{6}{42}+\dfrac{29}{42}\right):\dfrac{1}{28}-8\)

\(=\dfrac{32}{42}\cdot28-8=32\cdot\dfrac{2}{3}-8=\dfrac{64}{3}-\dfrac{24}{3}=\dfrac{40}{3}\)

d: \(-1\dfrac{5}{7}\cdot15+\dfrac{2}{7}\cdot\left(-15\right)+\left(-105\right)\left(\dfrac{2}{3}-\dfrac{4}{5}+\dfrac{1}{7}\right)\)

\(=-\dfrac{12}{7}\cdot15+\dfrac{2}{7}\cdot\left(-15\right)+\left(-105\right)\left(\dfrac{70}{105}-\dfrac{84}{105}+\dfrac{15}{105}\right)\)

\(=\dfrac{-180-30}{7}+\left(-105\right)\cdot\dfrac{1}{105}\)

=-30-1=-31

Bài 19:

a: \(A=7x-2x-\dfrac{2}{3}y+\dfrac{7}{9}y=5x+y\left(\dfrac{7}{9}-\dfrac{2}{3}\right)=5x+\dfrac{y}{9}\)

Khi x=-1/10;y=4,8 thì \(A=5\cdot\dfrac{-1}{10}+\dfrac{4.8}{9}\)

\(=-\dfrac{1}{2}+\dfrac{8}{15}=\dfrac{-15+16}{30}=\dfrac{1}{30}\)

b: \(B=x+\dfrac{0,2-0,375+\dfrac{5}{11}}{-0,3+\dfrac{9}{16}-\dfrac{15}{22}}\)

\(=x+\dfrac{\dfrac{2}{10}-\dfrac{6}{16}+\dfrac{10}{22}}{-\dfrac{3}{10}+\dfrac{9}{16}-\dfrac{15}{22}}=x+\dfrac{2\left(\dfrac{1}{10}-\dfrac{3}{16}+\dfrac{5}{22}\right)}{-3\left(\dfrac{1}{10}-\dfrac{3}{16}+\dfrac{5}{22}\right)}\)

\(=x-\dfrac{2}{3}\)

Khi x=-1/3 thì \(B=-\dfrac{1}{3}-\dfrac{2}{3}=-\dfrac{3}{3}=-1\)