-2/3 + (-0.6) - 7/10
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5 năm rồi , nếu biết bài này thì chị up hộ em bài giải câu b với =)
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k = ( 0,75 - 0, 6 + 3/7 + 3/3) : ( 11/7 + 11/3 + 2,75 + 2,2)
= ( 3/4 + 3/5 + 3/7 + 3/3) : ( 11/7 + 11/3 + +11/4 + 11/5 )
= 3 x (1/4 + 1/5 + 1/7 +1/3) : 11 x ( 1/7 + 1/3 + 1/4 + 1/5)
= 3/11
( Xem lại xem 3/3 hay 3/13)
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=43/306:599/105x1473/1820
=1505/61098x1473/1820
=0.01993613035
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\(\frac{0.18.1230+0.6.4567.2+3.5310.0.6}{1+4+7+10+...+52+55-514}=\frac{0+0+0}{1+4+7+10+...+52+55-514}=0\)
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\(\left(\frac{7}{3}\times x-0.6\right)\div3\frac{2}{5}=1\)
\(\left(\frac{7}{3}\times x-\frac{3}{5}\right)\div\frac{17}{5}=1\)
\(\frac{7}{3}\times x-\frac{3}{5}=1\times\frac{17}{5}\)
\(\frac{7}{3}\times x=\frac{17}{5}+\frac{3}{5}\)
\(\frac{7}{3}\times x=4\)
\(x=4\div\frac{7}{3}\)
\(x=4\times\frac{3}{7}\)
\(x=\frac{12}{7}\)
\(x=1\frac{5}{7}\)
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-0,6x - \(\frac{7}{3}=5,4\)
\(-0.6x=5,4+\frac{7}{3}\)
\(-0.6x=\frac{116}{15}\)
\(x=\frac{-116}{9}\)
Vậy \(x=\frac{-116}{9}\)
\(\dfrac{-2}{3}+\left(-0,6\right)-\dfrac{7}{10}\\ =\dfrac{-2}{3}-\dfrac{3}{5}-\dfrac{7}{10}\\ =\dfrac{-20}{30}-\dfrac{18}{30}-\dfrac{21}{30}\\ =\dfrac{-20-18-21}{30}\\ =\dfrac{-59}{30}\)
\(\dfrac{-2}{3}+\left(-0,6\right)-\dfrac{7}{10}\\ =\dfrac{-2}{3}-\dfrac{6}{10}-\dfrac{7}{10}\\ \dfrac{-20}{30}-\dfrac{18}{30}-\dfrac{21}{30}=\dfrac{-38}{30}-\dfrac{21}{30}=\dfrac{-59}{30}\)