5: ] ( 85 - 35 : 7 ) : 8 + 90 ] -52. 2
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a: \(2^3-5^3:5^2+12\cdot2^2\)
\(=8-5+48\)
\(=51\)
b: \(5\cdot\left[\left(85-35:7\right):8+90\right]-5\)
\(=5\cdot\left[10+90\right]-5\)
=495
5 x [(85 - 35 : 7) : 8 + 90] - 50
= 5 x [(85 - 5) : 8 + 90] - 50
= 5 x [80 : 8 + 90] - 50
= 5 x [10 + 90] - 50
= 5 x 100 - 50
= 500 - 50
= 450
\(5\times\left[\left(85-35:7\right):8+90\right]-50\\ =5\times\left[\left(85-5\right):8+90\right]-50\\ =5\times\left[80:8+90\right]-50\\ =5\times\left[10+90\right]-50\\ =5\times100-50\\ =500-50=450\)
5[(85 - 35 : 7) : 8 + 90] - 50
= 5[(85 - 5) : 8 + 90] - 50
= 5.[ 80 : 8 + 90] - 50
= 5.[ 10 + 90 ] - 50
= 5. 100 - 50
= 500 - 50
= 450
5[(85 - 35 : 7) : 8 + 90] - 50
= 5[(85 - 5) : 8 + 90] - 50
= 5.[ 80 : 8 + 90] - 50
= 5.[ 10 + 90 ] - 50
= 5. 100 - 50
= 500 - 50
= 450
\(2^3-5^3:5^2+12\cdot2^2=8-5+48=51\\ 5\left[\left(85-35:7\right):8+90\right]-5\cdot2^2\\ =5\left(80:8+90\right)-20=5\cdot100-20=480\)
\(5.\left[\left(85-35:7\right):8+90\right]\)
\(=5.\left[\left(85-5\right):8+90\right]\)
\(=5.\left(80:8+90\right)\)
\(=5.\left(10+90\right)\)
\(=5.100\)
\(=500\)
\(5\left[\left(85-35:7\right):8+90\right]\)
\(=5\left[\left(85-5\right):8=90\right]-50\)
\(=5\left[80:8+90\right]-50\)
\(=5\left[10+90\right]-50\)
\(=5.100-50\)
\(=450\)
a) 23.15 -[115-(12-5)2 ]
= 23.15 -[115-36]
= 8.15 -79
= 120-79
=41
b)5.[(85 - 35 : 7) :8 + 90 ] - 50
=5 .[80:8+90]-50
=5.100-50
=500-50
=450
c){[261 - ( 36-31)3.2 ]-9}.1001
={[261 - 125.2 ]-9}.1001
={[261 -250 ]-9}.1001
={11-9}.1001
=2.1001
=2002
d)3.102 - [1200 - ( 42 - 2.3)3]
=3.100-[1200 -(16-6)3 ]
=300-[1200-1000]
=300-200
=100
(5 + 6 + 11 - 41) x (1 + 2 + 3 + ... + 100)
= [(5 + 6) - (11 - 41)] x (1 + 2 +...+ 100)
= [11 - 30 ] x (1 + 2 + ... + 100)
= - 19 x (1 + 2 +...+ 100)
Lớp 5 chưa học số âm.
12 x 85 + 35 - 182 - 35 x 94
= 1020 - 35 x (94 - 1) - 182
= 1020 - 35 x 93 - 182
= 1020 - 3255 - 182
= - 2235 - 182
= - 2417
Lớp 5 chưa học số âm
`5 :[(85 - 35 : 7) : 8 + 90] - 5^2 .2`
`= 5 : (80 : 8 + 90) - 50`
`= 5 : 100 - 50`
`= 0,05 - 50 = -49,95`