2.x + 4.x=10.5+4
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`#` `\text{dkhanhqlv}`
`4)`
`a)3.(-5/11)`
`=-15/11`
`b)3/5+4/7 . 14/6`
`=3/5 + 4/3`
`=9/15+20/15`
`=29/15`
`c) 10/21-3/8 . 4/15`
`=10/21-1/10`
`=100/210-21/210`
`=79/100`
`d)(2/3+3/4)(5/7+5/14)`
`=(8/12+9/12)(10/14+5/14)`
`=17/12 . 15/14`
`=85/56`
`5)`
`a)x-1/2=3/10 . 5/6`
`=>x-1/2=1/4`
`=>x=1/4+1/2`
`=>x=1/4+2/4`
`=>x=3/4`
`b)x/5 = -3/14`
`=>x : 5 = -3/14`
`=>x=-3/14 . 5`
`=>x=-15/14`
`c)x+2/3=9/15 . 5/27`
`=>x+2/3=1/9`
`=>x=1/9-2/3`
`=>x=1/9-6/9`
`=>x=-5/9`
a) 10 - x : 2 = 1
x: 2 = 9
x = 18
b) x:4 + 3 x 2 = 7
x:4 + 6 = 7
x:4 = 1
x = 4
c) 2: x + 5 = 6
2: x = 1
x = 2
+4.10-x:2=1
40-x:2=1
x:2=40-1
x:2=39
x:2=19,5
+5.x:4+3*2=7
5.x:4+6=7
5.x:4=7-6=1
5.x=1.4=4
x=4:5
x=0,8
+6.2:x+5=6
12:x=6-5
12:x=1
x=12:1
x=12
+7.2*x*3*5=30
14.x.15=30
14.x=2
x=2:14
x=1/7
+8.2*x:10*2=1
16.x:20=1
16.x=20
x=20:16
x=1,25
9.18:x-5*2=8
10.5*5-2:x=24
a) (x-1)^x +2 = (x-1)^x +4
(x-1)^x - (x-1)^x = 4-2
0x = 2
=> \(x=\varphi\)
b) \(\frac{1}{4}\cdot\frac{2}{6}\cdot\frac{3}{8}\cdot\frac{4}{10}\cdot\frac{5}{12}\cdot...\cdot\frac{30}{62}\cdot\frac{31}{64}=2^x\)
\(\frac{1\cdot2\cdot3\cdot4...\cdot30\cdot31}{2^{32}\left(1\cdot2\cdot3\cdot4\cdot...\cdot30\cdot31\right)\cdot32}=2^x\)
\(\frac{1}{64}=2^x\)
\(2^{-6}=2^x\)
\(x=-6\)
\(4) 10-x:2=1 \)
\(=> x:2=10-1\)
\(=> x:2=9\)
\(=> x=9.2\)
\(=> x=18\). Vậy \(x=18\)
\(5) x:4+3.2=7\)
\(=> x:4+6=7\)
\(=> x:4=7-6\)
\(=> x:4=1\)
\(=> x=4\). Vậy \(x=4\)
\(6) 2:x+5=6\)
\(=> 2:x=6-5\)
\(=> 2:x=1\)
\(=> x=2\).Vậy \(x=2\)
\(7) 2.x.3.5=30\)
\(=> 2x.15=30\)
\(=>2x=30:15\)
\(=> 2x=2\)
\(=> x=1\).Vậy \(x=1\)
\(8)2.x:10.2=1\)
\(=> 2x=1:2.10\)
\(=> 2x=5\)
\(=>x=5:2\)
\(=> x=\frac{5}{2}\).Vậy \(x=\frac{5}{2}\)
\(9)18:x-5.2=8\)
\(=> 18:x-10=8\)
\(=>18:x=8+10\)
\(=>18:x=18\)
\(=> x=1\).Vậy \(x=1\)
\(10)5.5-2:x=24\)
\(=>25-2:x=24\)
\(=> 2:x=25-24\)
\(=>2:x=1\)
\(=>x=2\).Vậy \(x=2\)
1.Ta có:
Ư(10)={1;2;5;10}.
Ư(20)={1;2;4;5;10;20}.
=> Ư(10;20)={1;2;5;10}
Cái dấu ^ là gì rồi tôi giải tiếp cho
mình làm câu cuối thôi nhé , những câu còn lại bạn tự làm đi , dễ mà :)))) chỉ cần quy đồng mẫu lên là được
\(=\frac{x+1}{58}+1+\frac{x+2}{57}+1=\frac{x+3}{56}+1+\frac{x+4}{55}\)
\(=\frac{x+59}{58}+\frac{x+59}{57}=\frac{x+59}{56}+\frac{x+59}{55}\)
\(=\frac{x+59}{58}+\frac{x+59}{57}-\frac{x+59}{56}-\frac{x+59}{55}=0\)
\(=\left(x+59\right)\left(\frac{1}{58}+\frac{1}{57}-\frac{1}{56}-\frac{1}{55}\right)=0\)
Vì \(\left(\frac{1}{58}+\frac{1}{57}-\frac{1}{56}-\frac{1}{55}\right)\) luôn khác 0
<=> x + 59 = 0
<=> x=-59
$2x+4x=10.5+4$
$(2+4).x=50+4$
$6x=54$
$x=54:6$
$x=9$