Tính nhanh
18 × ( 19191919/21212121 + 88888/99999
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= 18 x \(\left(\frac{19.1010101}{21.1010101}+\frac{8.11111}{9.11111}\right)\)= 18 x ( \(\frac{19}{21}+\frac{8}{9}\)) = 9 x 2 ( \(\frac{57+56}{63}\))
= 9 x 2 x \(\frac{113}{63}\)=\(\frac{226}{7}\)
\(=18x\frac{19x1010101}{21x1010101}+\frac{8x11111}{9x11111}=18x\frac{19}{21}+\frac{8}{9}\)
a) Đặt A= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256
2A= 2(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256)
= 1+1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
=>A = 2A-A =1+1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 -1/2 - 1/4 - 1/8 - 1/16 - 1/32 - 1/64 - 1/128 - 1/256
=1-1/256
=255/256
b) = 18 - (19/21 + 8/9) = 18 - 113/63 = 1021/63
\(=18\times\left(\frac{19}{21}+\frac{8}{9}\right)=18\times\frac{113}{63}=\frac{226}{7}\)
\(18.\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)=18.\left(\frac{19}{21}+\frac{8}{9}\right)=18.\frac{113}{63}=\frac{226}{7}nha!!!!!\)
\(18\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)\)
\(=18\left(\frac{19}{21}+\frac{8}{9}\right)\)
\(=18\left(\frac{57}{63}+\frac{56}{63}\right)\)
\(=18\left(\frac{113}{63}\right)\)
\(=\frac{3^2.2.113}{3^2.7}\)
\(=\frac{226}{7}\)
$18\times\left(\frac{19191919}{21212121}+\frac{88888}{99999}\right)$
$=18\times\left(\frac{19}{21}+\frac{8}{9}\right)$
$=18\times\frac{113}{63}=\frac{226}{7}$
Lời giải:
$18\times (\frac{19191919}{21212121}+\frac{88888}{99999})$
$=18\times (\frac{19}{21}+\frac{8}{9})=18\times \frac{113}{63}=\frac{226}{7}$