3 + X + 2 x X=805
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64 x X + X + 32 x X + X x 3 = 805
(64+1+32+3) x X = 805
100 x X = 805
X = 805: 100
X = 8,05
2008 x 68 + 32 x 2008
= 2008 x (68 +32)
= 2008x100= 200800
64 x X + X + 32 x X + X x 3 = 805
X x ( 64 + 1 + 32 + 3 ) = 805
X x ( 65 + 35 ) = 805
X x 100 = 805
X = 805 : 100
X = 8,05
2008 x 68 + 32 x 2008
= 2008 x ( 68 + 32 )
= 2008 x 100
= 200800
bạn ơi
đề bài là tìm x nhưng sao ở trong bài lại y z
mk ko hiểu
50 x 125 x 2 x 8 x 805
(50 . 2).(125. 8). 805
100. 1000 . 805
100000. 805
80500000
chúc bạn học tốt!!!
50 x 125 x 2 x 8 x 805
= ( 50 x 2 ) x ( 125 x 8 ) x 805
= 100 x 1000 x 805
= 100 000 x 805
= 80 500 000
_HT_
( y xy) x 8 = 805 - 15 : 3
( y xy) x 8 = 800
(y xy) x 8 = 800 : 8
( y xy) x 8 = 100
nhung chi co 50 x 2 = 100.
vay y = 50.
a) 35 × x = 805
x = 805 : 35
x = 23
b) x : 37 + 1238 = 1644
x : 37 = 1644 - 1238
x : 37 = 406
x = 406 × 37
x = 15022
20.11x194+20.11x805+20.11
=20.11x(194+805+1)
=20.11x1000=20110
X x 3.4 +X x1.2=23
X x( 3.4+1.2)=23
X x 4.6=23
X=23 :4.6=5
* \(20,11.194+20,11.805+20,11\)
\(=20,11.\left(194+805+1\right)\)
\(=20,11.1000\)
\(=20110\)
* \(x.3,4+x.1,2=23\)
\(\Leftrightarrow x.\left(3,4+1,2\right)=23\)
\(\Leftrightarrow x.4,6=23\)
\(\Leftrightarrow x=23:4,6\)
\(\Leftrightarrow x=5\)
(Nhớ k cho mình với nha!)
x=79
nên x+1=80
\(P\left(x\right)=-80x^6+80x^5-80x^4+...+80x+15\)
\(=-x^6\left(x+1\right)+x^5\left(x+1\right)-x^4\left(x+1\right)+...+x\left(x+1\right)+15\)
\(=-x^7-x^6+x^6+x^5-x^5-x^4+...+x^2+x+15\)
\(=-x^7+x+15\)
\(=-79^7+79+15\)
\(=-79^7+94\)
\(x=79\Leftrightarrow x+1=80\\ \Leftrightarrow P\left(x\right)=-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+...+\left(x+1\right)x+15\\ P\left(x\right)=-x^7-x^6+x^6+x^5-x^5-x^4+...+x^2+x+15\\ P\left(x\right)=-x^7+x+15=-79^7+94\)
\(\frac{1}{9x10}\)\(+\frac{1}{10x11}\)\(+\frac{1}{11x12}\)\(+.....\)\(+\frac{1}{805x806}\)
\(=\frac{1}{9}\)\(-\frac{1}{10}\)\(+\frac{1}{10}\)\(-\frac{1}{11}\)\(+\frac{1}{11}\)\(-\frac{1}{12}\)\(+.....\frac{1}{805}\)\(-\frac{1}{806}\)
\(=\frac{1}{9}\)\(-\frac{1}{806}\)
\(=\frac{797}{7254}\)
\(3+x+2\times x=805\\ 3+3\times x=805\\ 3\times x=805-3\\ 3\times x=802\\ x=\dfrac{802}{3}\)
\(3+x+2\times x=805\)
\(3+x\times\left(1+2\right)=805\)
\(3+x\times3=805\)
\(x\times3=805-3\)
\(x\times3=802\)
\(x\) \(=802:3\)
\(x\) \(=\dfrac{802}{3}\)