Question

[Long Trương Thành]

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Answer 1

[Nguyễn Lê Phước Thịnh]

\(C=\left(6-\dfrac{2}{3}+\dfrac{5}{16}\right)-\left(2+\dfrac{4}{3}-\dfrac{7}{8}\right)-\left(6-\dfrac{5}{8}+\dfrac{13}{12}\right)\)

\(=6-\dfrac{2}{3}+\dfrac{5}{16}-2-\dfrac{4}{3}+\dfrac{7}{8}-6+\dfrac{5}{8}-\dfrac{13}{12}\)

\(=\left(6-2-6\right)+\left(-\dfrac{2}{3}-\dfrac{4}{3}\right)+\left(\dfrac{5}{16}+\dfrac{7}{8}+\dfrac{5}{8}\right)-\dfrac{13}{12}\)

\(=-2-2+\left(\dfrac{5}{16}+\dfrac{12}{8}\right)-\dfrac{13}{12}\)

\(=-4-\dfrac{13}{12}+\dfrac{29}{16}=-\dfrac{157}{48}\)

Answer 2

[HT.Phong (9A5)]

\(C=\left(6-\dfrac{2}{3}-\dfrac{5}{10}\right)-\left(2+\dfrac{4}{3}-\dfrac{7}{8}\right)-\left(6-\dfrac{5}{8}+\dfrac{13}{12}\right)\)

\(=6-\dfrac{2}{3}-\dfrac{5}{10}-2-\dfrac{4}{3}+\dfrac{7}{8}-6+\dfrac{5}{8}-\dfrac{13}{12}\)

\(=\left(6-2-6\right)+\left(-\dfrac{2}{3}-\dfrac{4}{3}\right)+\left(\dfrac{7}{8}+\dfrac{5}{8}\right)+\left(\dfrac{-5}{10}-\dfrac{13}{12}\right)\)

\(=\left(-2\right)+\left(-2\right)+\dfrac{3}{2}+\dfrac{-19}{12}\)
\(=\left(-4\right)+\dfrac{18}{12}+\dfrac{-19}{12}\)

\(=\left(-4\right)+\dfrac{-1}{12}\)

\(=\dfrac{-48}{12}+\dfrac{-1}{12}\)

\(=\dfrac{-49}{12}\)