a)1/2 < 12/a < 4/3
b)14/5 < a/5 < 4
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a,\(\frac{14}{3}\)> \(\frac{42}{11}\)
b, 0 < \(\frac{1}{2}\)+ \(\frac{1}{3}\)+ \(\frac{1}{6}\)
c, 0 < 1 < \(\frac{1}{4}\)+ \(\frac{5}{6}\)+ \(\frac{11}{12}\)
a: \(\dfrac{1}{3}+\dfrac{3}{35}< \dfrac{x}{210}< \dfrac{4}{7}+\dfrac{3}{5}+\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{70}{210}+\dfrac{18}{210}< \dfrac{x}{210}< \dfrac{120}{210}+\dfrac{126}{210}+\dfrac{105}{210}\)
\(\Leftrightarrow88< x< 441\)
b: Ta có: \(\dfrac{5}{3}+\dfrac{-14}{3}< x< \dfrac{8}{5}+\dfrac{18}{10}\)
\(\Leftrightarrow\dfrac{5}{3}-\dfrac{14}{3}< x< \dfrac{8}{5}+\dfrac{9}{5}\)
=>-9/3<x<17/5
=>-3<x<3,4
mà x là số nguyên
nên \(x\in\left\{-2;-1;0;1;2;3\right\}\)
a) Ta có:
\(-\dfrac{3}{4}< \dfrac{a}{12}< -\dfrac{5}{9}\)
hay \(-\dfrac{27}{36}< \dfrac{3a}{36}< -\dfrac{20}{36}\)
\(\Rightarrow-27< 3a< -20\)
\(\Rightarrow3a\in\left\{-26;-25;-24;-23;-22;-21\right\}\)
Mà \(a\) là số nguyên suy ra:
\(a=-8\)
1.a)-4<x<3
=> x={-3;-2;-1;0;1;2}
b)-5<x<5
=>x={-4;-3;-2;-1;0;1;2;3;4}
2.a)1+(-3)+5+(-7)+9+(-11)
=(1+5+9)+[(-3)+(-7)+(-11)]
=15+(-21)
=-6
b)(-2)+4+(-6)+8+(-10)+12
=[(-2)+(-6)+(-10)]+(4+8+12)
=(-18)+24
=6
tick cho mk nha bạn
a, \(\dfrac{1}{2}< \dfrac{12}{a}< \dfrac{4}{3}\Leftrightarrow\dfrac{1}{24}< \dfrac{1}{a}< \dfrac{1}{9}\Leftrightarrow9< a< 24\)
b, \(\dfrac{14}{5}< \dfrac{a}{5}< 4\Leftrightarrow14< a< 20\)
a) \(\dfrac{1}{2}< \dfrac{12}{a}< \dfrac{4}{3}\)
\(6\cdot\dfrac{1}{2}< 6\cdot\dfrac{12}{a}< 6\cdot\dfrac{4}{3}\)
\(3< \dfrac{72}{a}< 8\)
\(\dfrac{72}{3}>a>\dfrac{72}{8}\)
\(24>a>9\)
Vậy: ...
b) \(\dfrac{14}{5}< \dfrac{a}{5}< 4\)
\(\dfrac{14}{5}\times5< a< 5\times4\)
\(14< a< 20\)