x mũ 3 - 4x = 0
help me please
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cảm ơn nhìu
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1.what do you think about the environment in your town?
In my hometown , people are not aware of environmental protection, there are still many people who are unaware and throw their garbage out, besides, there are still people who pick up trash and throw it in the right place.
Every day on the news reports, the news is everywhere, saying phrases like melting ice, global warming, acid rain, global climate change or adding new lands to become industrial landfills. All are consequences of environmental pollution.
You can refer this one:
Recycle/Reuse Your Books. ...
Ditch the Paper. ...
Buy a Water Bottle. ...
Turn Off Your Phone. ...
Recycle. ...
Avoid Public Transport When Possible. ...
Save Water. ...
Save Electricity.
PT có 2 nghiệm `<=> \Delta' >=0`
`<=> 4(2m+3)^2 -4(4m^2-3) >=0`
`<=>16m^2+48m+36-16m^2+12>=0`
`<=>m >= -1`
Viet: `{(x_1+x_2=-2m-3),(x_1x_2=4m^2-3):}`
Theo đề: `x_1^2+x_2^2=1/2`
`<=>(x_1+x_2)^2-2x_1x_2=1/2`
`<=>(-2m-3)^2 -2(4m^2-3)=1/2`
`<=>-4m^2+12m+15=1/2`
`<=>` \(\left[{}\begin{matrix}m=\dfrac{6+\sqrt{94}}{4}\left(TM\right)\\m=\dfrac{6-\sqrt{94}}{4}\left(L\right)\end{matrix}\right.\)
Vậy....
\(x^4\cdot x^7\cdot...\cdot x^{100}\)
\(=x^{4+7+...+100}\)
\(=x^{52\cdot33}=x^{1716}\)
\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}\)
Ta có : \(x^1\cdot x^2=x^{1+2}=x^3\)
Tương tự : \(x^1\cdot x^2\cdot x^3=x^{1+2+3}=x^6\)
Áp dụng vào bài toán :
\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}=x^{1+2+3+...+2006}\)
\(\Rightarrow x^{1+2+3+...+2006}=x^{2013021}\)
Em tham khảo:
“Ong trại” có nghĩa là một phần đàn ong rời bỏ tổ nhà, mang theo một ong chúa – con duy nhất trong đàn ong có khả năng sinh sản.
7(x - 3) - x(3 - x)
= (x - 3)(7 + x)
chỉ bt có v mà k bt có đúng k
1 ) 7 ( x - 3 ) - x ( 3 - x )
= 7 ( x - 3 ) + x ( x - 3 )
= ( x - 3 ) ( 7 + x )
2 ) 4x2 - 6x + 3 - 2x
= 4x2 - 2x - 6x + 3
= 2x ( 2x - 1 ) - 3 ( 2x - 1 )
= ( 2x - 1 ) ( 2x - 3 )
3 ) ( 4 - x ) - 4x + x2
= ( 4 - x ) - x ( 4 - x )
= ( 4 - x ) ( 1 - x )
4 ) x2 - 2xy + y2
= ( x - y )2
turn ....the lights when we go out
A.on B.off C.of
we will have a smart phone to...... the internet
A.get B.do C.surt D.send
x3 - 4x = 0
Có 2 TH:
TH1:
x3 = 0
x = 0
TH2:
4x = 0
x = 0 : 4
x = 0
=> x = 0
x\(^3\)-4x =0
x.(x\(^2\)- 4) = 0
\(\orbr{\begin{cases}x=0\\x^2-4=0\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=0\\x=2\end{cases}}\)