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Bài 2:
a: \(\dfrac{1}{2x^3y}=\dfrac{6yz^3}{12x^3y^2z^3}\)
\(\dfrac{2}{3xy^2z^3}=\dfrac{2\cdot4x^2}{12x^3y^2z^3}=\dfrac{8x^2}{12x^3y^2z^3}\)
\(\dfrac{x^2-4}{x^2+2x}=\dfrac{\left(x-2\right)\left(x+2\right)}{x\left(x+2\right)}=\dfrac{x-2}{x}=\dfrac{\left(x-2\right)^2}{x\left(x-2\right)}\)
\(\dfrac{x}{x-2}=\dfrac{x^2}{x\left(x-2\right)}\)
a) MTC: 2xy
Quy đồng: \(\frac{2x-3y}{2xy}\) giữ nguyên
\(\frac{x+2y}{x}=\frac{2y\left(x+2y\right)}{2xy}=\frac{2xy+y^2}{2xy}\)
b) \(\frac{2}{x^2-4x}=\frac{2}{x\left(x-4\right)};\frac{x}{x^2-16}=\frac{x}{\left(x-4\right)\left(x+4\right)}\)
MTC: x (x-4)(x+4)
Quy đồng : \(\frac{2}{x\left(x-4\right)}=\frac{2\left(x+4\right)}{x\left(x-4\right)\left(x+4\right)}=\frac{2x+8}{x\left(x-4\right)\left(x+4\right)}\)
\(\frac{x}{\left(x+4\right)\left(x-4\right)}=\frac{x^2}{x\left(x-4\right)\left(x+4\right)}\)
Học tốt nhé ^3^
b)\(\frac{10}{x + 2} ; \frac{5}{2 x - 4} ; \frac{1}{6 - 3 x}\)
Giải:
a)
\(x^{3} - 1 = \left(\right. x - 1 \left.\right) \left(\right. x^{2} + x + 1 \left.\right)\)
Mẫu chung: \(\left(\right. x - 1 \left.\right) \left(\right. x^{2} + x + 1 \left.\right)\)
\(\frac{4 x^{2} - 3 x + 5}{\left(\right. x - 1 \left.\right) \left(\right. x^{2} + x + 1 \left.\right)} ; \frac{\left(\right. 1 - 2 x \left.\right) \left(\right. x - 1 \left.\right)}{\left(\right. x - 1 \left.\right) \left(\right. x^{2} + x + 1 \left.\right)} ; \frac{- 2}{\left(\right. x - 1 \left.\right) \left(\right. x^{2} + x + 1 \left.\right)}\)
b)
\(2 x - 4 = 2 \left(\right. x - 2 \left.\right) , 6 - 3 x = 3 \left(\right. 2 - x \left.\right) = - 3 \left(\right. x - 2 \left.\right)\)
Mẫu chung:
\(6 \left(\right. x + 2 \left.\right) \left(\right. x - 2 \left.\right)\) \(\frac{60 \left(\right. x - 2 \left.\right)}{6 \left(\right. x + 2 \left.\right) \left(\right. x - 2 \left.\right)} ; \frac{15 \left(\right. x + 2 \left.\right)}{6 \left(\right. x + 2 \left.\right) \left(\right. x - 2 \left.\right)} ; - \frac{2 \left(\right. x + 2 \left.\right)}{6 \left(\right. x + 2 \left.\right) \left(\right. x - 2 \left.\right)}\)
a,\(\frac{2x^2+4x}{x+2}\)=\(\frac{2x\left(x+2\right)}{x+2}\)\(=2x\)
b, \(\frac{3x}{2x+4}\)=\(\frac{3x^2-6x}{2\left(x+2\right)\left(x-2\right)}\)
\(\frac{x+3}{x^2+4}\)=\(\frac{2x+6}{2\left(x-2\right)\left(x+2\right)}\)
tick mình nhé!!
a: 1/x^2y=1/x^2y
3/xy=3x/x^2y
b: \(\dfrac{x}{x^2+2xy+y^2}=\dfrac{x}{\left(x+y\right)^2}\)
\(\dfrac{2x}{x^2+xy}=\dfrac{2}{x+y}=\dfrac{2x+2y}{\left(x+y\right)^2}\)
