0,3 × (y + 1/3) = 1/2 × (0,81 :2,7)
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\(0,3.\left(x.\frac{1}{3}\right)=\frac{1}{2}.\left(0,81:2,7\right)\)
\(0,3.\left(x.\frac{1}{3}\right)=\frac{1}{2}.\frac{3}{10}\)
\(0,3.\left(x.\frac{1}{3}\right)=\frac{3}{20}\)
\(\frac{1}{3}x=\frac{3}{20}:0,3\)
\(\frac{1}{3}x=\frac{1}{2}\)
\(x=\frac{1}{2}:\frac{1}{3}\)
\(x=\frac{3}{2}\)
Vậy x = 3/2
a, y + y : 0, 5 + y : 0,25 = 1,05
y x 1 + y x 2 + y x 4 = 1,05
y x ( 1 + 2 + 4 ) = 1,05
y x 7 = 1,05
y = 1,05 : 7
y = 0,15
0,3 . ( x + 1/3 ) = 1/2 . ( 0,81 : 2,7 )
0,3 . ( x + 1/3 ) = 1/2 . 0,3
0,3 . ( x + 1/3 ) = 0,15
( x + 1/3 ) = 0,15 : 0,3
x + 1/3 = 0,5
x = 0,5 - 1/3
x = 0,1666...
\(a,\frac{7011}{25}:\left(x-42,6\right)=117,14-47,03\)
\(=\frac{7011}{25}:\left(x-42,6\right)=70,11\)
\(\Rightarrow\left(x-42,6\right)=\frac{7011}{25}:70,11\)
\(\Rightarrow x=4+42,6\)
\(\Rightarrow x=46,6\)
\(0,3\times\left(y+\dfrac{1}{3}\right)=\dfrac{1}{2}\times\left(0,81:2,7\right)\)
=>\(0,3\times\left(y+\dfrac{1}{3}\right)=\dfrac{1}{2}\times0,3\)
=>\(y+\dfrac{1}{3}=\dfrac{1}{2}\)
=>\(y=\dfrac{1}{2}-\dfrac{1}{3}=\dfrac{1}{6}\)
Đề bài : 0,3 x ( y + \(\dfrac{1}{3}\) ) = \(\dfrac{1}{2}\) x ( 0,81 : 2,7)
\(\dfrac{3}{10}\) x ( y + \(\dfrac{1}{3}\) ) = \(\dfrac{1}{2}\) x ( \(\dfrac{81}{100}\) : \(\dfrac{27}{10}\))
\(\dfrac{3}{10}\) x ( y + \(\dfrac{1}{3}\) ) = \(\dfrac{1}{2}\) x ( \(\dfrac{81}{100}\) x \(\dfrac{10}{27}\) )
\(\dfrac{3}{10}\) x ( y + \(\dfrac{1}{3}\) ) = \(\dfrac{1}{2}\) x \(\dfrac{3}{10}\)
\(\dfrac{3}{10}\) x ( y + \(\dfrac{1}{3}\) ) = \(\dfrac{3}{20}\) y + \(\dfrac{1}{3}\) = \(\dfrac{3}{20}\) : \(\dfrac{3}{10}\) = \(\dfrac{3}{20}\) x \(\dfrac{10}{3}\) y + \(\dfrac{1}{3}\) = \(\dfrac{1}{2}\) y = \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) y = \(\dfrac{3}{6}\) - \(\dfrac{2}{6}\) y = \(\dfrac{1}{6}\)