\(1\dfrac{14}{17}\)-\(\dfrac{6}{11}\)+\(\dfrac{-5}{11}\)-\(\dfrac{-20}{17}\)
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30 tháng 5 2022
a: \(=\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{-5}{13}-\dfrac{8}{13}\right)+\left(\dfrac{-18}{35}-\dfrac{17}{35}\right)\)
=1-1-1
=-1
b: \(=\dfrac{-3}{8}\left(\dfrac{1}{6}+\dfrac{5}{6}\right)+\dfrac{-5}{8}=\dfrac{-3}{8}-\dfrac{5}{8}=-1\)
c: \(=\dfrac{4}{4}\cdot\dfrac{5}{15}\cdot\dfrac{11}{11}=\dfrac{1}{3}\)
TC
30 tháng 5 2022
a)\(=\left(-\dfrac{5}{13}+\dfrac{-8}{13}\right)+\left(-\dfrac{18}{35}-\dfrac{17}{35}\right)+\left(\dfrac{3}{14}+\dfrac{14}{17}\right)=-1-1+1=-1\)
b)\(=\dfrac{-3}{8}.\left(\dfrac{1}{6}+\dfrac{5}{6}\right)-\dfrac{10}{16}=-\dfrac{3}{8}.1-\dfrac{10}{16}=-\dfrac{6}{16}-\dfrac{10}{16}=-\dfrac{16}{16}=-1\)
c)\(\dfrac{-4.5.11}{11.5.3.-4}=\dfrac{1}{3}\)
LT
6 tháng 1 2021
\(\dfrac{4}{11}< \dfrac{6}{11}\)
\(\dfrac{6}{7}=\dfrac{12}{14}\)
\(\dfrac{15}{17}>\dfrac{10}{17}\)
\(\dfrac{2}{3}< \dfrac{3}{4}\)
8 tháng 12 2022
411<611411<611
67=121467=1214
1517>10171517>1017
23<34
hoc tot nhe
1 kg 
2 m
H
24 tháng 8 2023
a)
\(\dfrac{5}{8}\left(kg\right)< \dfrac{6}{8}\left(kg\right)\)
Do 13 > 12 nên \(\dfrac{13}{12}>1\)
hay: \(\dfrac{13}{12}\left(kg\right)>1\left(kg\right)\)
b)
\(\dfrac{11}{12}\left(l\right)>\dfrac{11}{14}\left(l\right)\)
Có:
\(\dfrac{5}{3}=\dfrac{5\times3}{3\times3}=\dfrac{15}{9}\)
nên: \(\dfrac{5}{3}\left(l\right)=\dfrac{15}{9}\left(l\right)\)
c)
\(\dfrac{5}{6}=\dfrac{5\times3}{6\times3}=\dfrac{15}{18n}\)
nên \(\dfrac{5}{6}\left(m\right)< \dfrac{17}{8}\left(m\right)\)
Có: \(2=\dfrac{2\times7}{7}=\dfrac{14}{7}\)
nên: \(\dfrac{16}{7}\left(m\right)>2\left(m\right)\)
1 tháng 5 2023
\(Q=\dfrac{5}{11}.\dfrac{2}{17}+\dfrac{7}{17}.\dfrac{-6}{11}-\dfrac{9}{17}.\dfrac{5}{11}\)
\(Q=\dfrac{5}{11}\left(\dfrac{2}{17}-\dfrac{9}{17}\right)+\dfrac{7}{17}.\dfrac{-6}{11}\)
\(Q=\dfrac{5}{11}.\dfrac{-7}{17}+\dfrac{-7}{17}.\dfrac{6}{11}\)
\(Q=\dfrac{-7}{17}.\left(\dfrac{5}{11}+\dfrac{6}{11}\right)\)
\(Q=\dfrac{-7}{17}\)
MD
18 tháng 8 2017
1,Ta có:\(\dfrac{9}{10}-\dfrac{1}{90}-\dfrac{1}{72}-\dfrac{1}{57}-\dfrac{1}{42}-\dfrac{1}{30}-\dfrac{1}{20}-\dfrac{1}{12}-\dfrac{1}{6}-\dfrac{1}{2}\) =\(\dfrac{9}{10}-\left(\dfrac{1}{90}+\dfrac{1}{72}+...+\dfrac{1}{2}\right)\)
= \(\dfrac{9}{10}-\left\{\dfrac{1}{\left(9.10\right)}+\dfrac{1}{\left(9.8\right)}+...+\dfrac{1}{\left(2.1\right)}\right\}\)
= \(\dfrac{9}{10}-\left(\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{8}-\dfrac{1}{9}+...+\dfrac{1}{1}-\dfrac{1}{2}\right).\left(\dfrac{1}{90}=\dfrac{1}{9.10}=\dfrac{1}{9}-\dfrac{1}{10}\right)\)=\(\dfrac{9}{10}-\left(1-\dfrac{1}{10}\right)\)
=\(\dfrac{9}{10}-\dfrac{9}{10}\)
= 0
Ý 2 dễ rồi bạn tự tính
BN
18 tháng 8 2017
1, \(\dfrac{9}{10}-\dfrac{1}{90}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-\dfrac{1}{30}-\dfrac{1}{20}-\dfrac{1}{12}-\dfrac{1}{6}-\dfrac{1}{2}\)
\(=\dfrac{9}{10}-\left(\dfrac{1}{90}+\dfrac{1}{72}+\dfrac{1}{56}+\dfrac{1}{42}+\dfrac{1}{30}+\dfrac{1}{20}+\dfrac{1}{6}+\dfrac{1}{2}\right)\)
\(=\dfrac{9}{10}-\left(\dfrac{1}{9.10}+\dfrac{1}{8.9}+...+\dfrac{1}{1.2}\right)\)
\(=\dfrac{9}{10}-\left(\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{7}-\dfrac{1}{8}+...+1-\dfrac{1}{2}\right)\)
\(=\dfrac{9}{10}-\left(\dfrac{-1}{10}+1\right)=\dfrac{9}{10}-\dfrac{9}{10}=0\)
2, \(\dfrac{-5}{11}\cdot\dfrac{13}{17}-\dfrac{5}{11}.\dfrac{4}{17}\)
\(=\dfrac{-5}{11}\cdot\dfrac{13}{17}+\dfrac{-5}{11}.\dfrac{4}{17}\)
\(=\dfrac{-5}{11}\left(\dfrac{13}{17}+\dfrac{4}{17}\right)=\dfrac{-5}{11}.1=\dfrac{-5}{11}\)
27 tháng 6 2023
a: =11+3/4-6-5/6+4+1/2+1+2/3
=10+9/12-10/12+6/12+8/12
=10+13/12=133/12
b: \(=2+\dfrac{17}{20}-1-\dfrac{11}{15}+2+\dfrac{3}{20}\)
=3-11/15
=34/15
c: \(=\dfrac{31}{7}:\left(\dfrac{7}{5}\cdot\dfrac{31}{7}\right)\)
\(=\dfrac{31}{7}:\dfrac{31}{5}=\dfrac{5}{7}\)
d: \(=\dfrac{29}{8}\cdot\dfrac{36}{29}\cdot\dfrac{15}{23}\cdot\dfrac{23}{5}=\dfrac{9}{2}\cdot3=\dfrac{27}{2}\)
11 tháng 3 2022
b: D=(-3/31-28/31)+(-6/17-11/17)+(1/25-5/25)
=-2-4/25=-54/25
MT
2
TA
23 tháng 7 2021
`17/20 = 119/140`
`11/14=110/140`
`=> 119/140 > 110/140`
`=> 17/20 > 11/14`
23 tháng 7 2021
\(\dfrac{17}{20}=\dfrac{17\cdot14}{20\cdot14}=\dfrac{238}{280}\)
\(\dfrac{11}{14}=\dfrac{11\cdot20}{14\cdot20}=\dfrac{220}{280}\)
mà 238>220
nên \(\dfrac{17}{20}>\dfrac{11}{14}\)
Q
24 tháng 7 2017
3) \(11\dfrac{1}{4}-\left(2\dfrac{5}{7}+5\dfrac{1}{4}\right)\)
\(=\dfrac{45}{4}-\left(7+\dfrac{27}{28}\right)\)
\(=\dfrac{45}{4}-7\dfrac{27}{28}\)
\(=\dfrac{45}{4}-\dfrac{223}{28}\)
\(=\dfrac{23}{7}\)
4) \(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{14}\)
\(=\dfrac{1386-14875-11250+7000-19125}{15750}\)
\(=-\dfrac{2048}{875}\)
1 14/17 - 6/11 + (-5/11) - (-20/17)
= 1 + 14/17 - (6/11 + 5/11) + 20/17
= 1 + (14/17 + 20/17) - 1
= 1 + 2 - 1
= 2
\(1\dfrac{14}{17}-\dfrac{6}{11}+\dfrac{-5}{11}-\dfrac{-20}{17}\)
\(=\dfrac{31}{17}-\dfrac{6}{11}-\dfrac{5}{11}+\dfrac{20}{17}\)
\(=\left(\dfrac{31}{17}+\dfrac{20}{17}\right)-\left(\dfrac{6}{11}+\dfrac{5}{11}\right)\)
\(=3-1=2\)