Chuyển về lũy thừa:
5^3x5x5^3:27=
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\(=\frac{3^6.9^4.5^4-3^{13}.5^{13}.5^9}{3^{12}.5^6+9^4.5^4}=\frac{3^6.3^8.5^4-3^{12}.5^{22}}{3^{12}.5^6+3^8.5^4}=\frac{5^4.3^{12}\left(3^{12}-5^{18}\right)}{5^4.3^8\left(3^4.5+1\right)}=\frac{3^4.\left(3^{12}-5^{18}\right)}{3^4.5+1}\)
\(\left(\dfrac{1}{27}\right)^5\) = \(\left(\dfrac{1}{3^3}\right)^5\) = \(\left(\dfrac{1}{3}\right)^{15}\)
\(\left(\dfrac{1}{27}\right)^5=\left[\left(\dfrac{1}{3}\right)^3\right]^5=\dfrac{1}{3}^{3.5}=\dfrac{1}{3}^{15}\)
1)Đưa về lũy thừa cùng cơ số 2
82= \(\left(2^3\right)^2=2^6\) 323= \(\left(2^5\right)^3=2^{15}\) 644= \(\left(2^6\right)^4=2^{24}\) 43= \(\left(2^2\right)^{^3}=2^6\)
2)Đưa về lũy thừa cùng cơ số 3
93= \(\left(3^2\right)^3=3^6\) 274= \(\left(3^3\right)^4=3^{12}\) 95= \(\left(3^2\right)^5=3^{10}\) 816= \(\left(3^4\right)^6=3^{24}\)
3)Đưa về lũy thừa cùng cơ số 2
83:42= \(\left(2^3\right)^3:\left(2^2\right)^2=2^9:2^4=2^5\) 162:32= \(\left(2^4\right)^2:2^5=2^8:2^5=2^3\)
\(64^4:4^3=\left(2^6\right)^4:\left(2^2\right)^3=2^{24}:2^6=2^{18}\) 323:82= \(\left(2^5\right)^3:\left(2^3\right)^2=2^{15}:2^6=2^9\)
b: \(2^{27}=8^9\)
\(3^{18}=9^9\)
mà 8<9
nên \(2^{27}< 3^{18}\)
Câu \(1.\)\(27^{15}:9^{21}=\left(3^3\right)^{15}:\left(3^2\right)^{21}=3^{45}:3^{42}=3^{45-42}=3^3=27\)
Câu \(2.\) \(4^{16}:8^{10}=\left(2^2\right)^{16}:\left(2^3\right)^{10}=2^{32}:2^{30}=2^{32-30}=2^2=4\)
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- Chúc các bn có nx ngày hè vui vẻ -
\(a,4^{10}\cdot8^{15}=2^{20}\cdot2^{45}=2^{65}\)
\(b,4^{15}\cdot5^{30}=4^{15}\cdot5^{15}\cdot5^{15}=\left(4\cdot5\cdot5\right)^{15}=100^{15}\)
\(c,27^{16}\cdot9^{10}=3^{48}\cdot3^{20}=3^{68}\)
a) \(4^{10}.8^{15}=\left(2^2\right)^{10}.\left(2^3\right)^{15}=2^{20}.2^{45}=2^{20+45}=2^{65}\)
b) \(4^{15}.5^{30}=\left(2^2\right)^{15}.5^{30}=2^{30}.5^{30}=\left(2.5\right)^{30}=10^{30}\)
c) \(27^{16}.9^{10}=\left(3^3\right)^{16}.\left(3^2\right)^{10}=3^{48}.3^{20}=3^{48+20}=3^{68}\)
\(27\cdot\left(-3\right)^5\cdot\left(-3\right)\cdot81=3^3\cdot\left(-3\right)^5\cdot\left(-3\right)\cdot3^4=3^7\cdot\left(-3\right)^6=3^7\cdot3^6=3^{13}\)
53.5.53:27=53+1+3:33=57:33
\(\frac{5^3.5.5^3}{27}\)
\(=\frac{5^{3+1+3}}{3^3}\)
\(=\frac{5^7}{3^3}\)