15x27-15x17/10x64-10/54=
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a)75x89+25x27+2x75 b)77x27+9x24+15x27
=25x3x89+25x27+2x3x25 =77x27+9x3x8+15x27
=25x(267+27+6) =77x27+27x8+15x27
=25x300 =27x(77+8+15)
=7500 =27x100=2700
Mình trả lời đầu tiên mà
a, 75 x 89 + 25 x 27 + 2 x 75
= 75 ( 89 + 2) + 25 x 27
= 3 x 25 x 91 + 25 x 27
= 25 x 273 + 25 x 27
= 25 x (273 + 27)
= 25 x 300
= 7500
a) Số số hạng là :
( 158 - 2 ) : 3 + 1 = 53 ( số hạng )
Tổng là :
( 158 + 2 ) x 53 : 2 = 4240
Đ/s : 4240
b) 75 x 89 + 25 x 27 + 2 x 75
= 75 x 89 + 25 x 3 x 9 + 2 x 75
= 75 x 89 + 75 x 9 + 2 x 75
= 75 x ( 89 + 2 + 9 )
= 75 x 100
= 7500
c) 77 x 27 + 9 x 24 + 15 x 27
= 77 x 27 + 9 x 3 x 8 + 15 x 27
= 77 x 27 + 27 x 8 + 15 x 27
= 27 x ( 77 + 8 + 15 )
= 27 x 100
= 2700
\(A=13.15+15.17+17.19+...+99.101\)
\(\Rightarrow6A=13.15.6+15.17.6+17.19.6+...+99.101.6\)
\(\Rightarrow6A=13.15.\left(17-11\right)+15.17.\left(19-13\right)+17.19.\left(21-15\right)+...+99.101.\left(103-97\right)\)
\(\Rightarrow6A=\left(13.15.17-11.13.15\right)+\left(15.17.19-13.15.17\right)+\left(17.19.21-15.17.19\right)+...+\left(99.101.103-97.99.101\right)\)
\(\Rightarrow6A=99.101.103-11.13.15\)
\(\Rightarrow6A=1027752\)
\(\Rightarrow A=171292\)
\(\text{Đặt }A=\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{13.15}+\frac{1}{15.17}\)
\(\Leftrightarrow2A=\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}+\frac{2}{15.17}\)
\(\Leftrightarrow2A=\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{15-13}{13.15}+\frac{17-15}{15.17}\)
\(\Leftrightarrow2A=\frac{5}{3.5}-\frac{3}{3.5}+\frac{7}{5.7}-\frac{5}{5.7}+...+\frac{17}{15.17}-\frac{15}{15.17}\)
\(\Leftrightarrow2A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}+...+\frac{1}{15}-\frac{1}{17}\)
\(\Leftrightarrow2A=\frac{1}{3}-\frac{1}{7}\)
\(\Leftrightarrow2A=\frac{4}{21}\)
\(\Rightarrow A=\frac{4}{21}\times\frac{1}{2}\)
\(\Rightarrow A=\frac{2}{21}\)
=4x(\(\frac{1}{11x13}\)+\(\frac{1}{13x15}\)+.......+\(\frac{1}{99x101}\))
=4x(\(\frac{1}{11}\)-\(\frac{1}{13}\)+\(\frac{1}{13}\)-\(\frac{1}{15}\)+....+\(\frac{1}{99}\)-\(\frac{1}{101}\))
4x(\(\frac{1}{11}\)-\(\frac{1}{101}\))
=4x \(\frac{90}{1111}\)
=\(\frac{360}{1111}\)
\(\frac{4}{11\times13}+\frac{4}{13\times15}+\frac{4}{15\times17}+...+\frac{4}{99\times101}\)
\(=\frac{4}{11}-\frac{4}{13}+\frac{4}{13}-\frac{4}{15}+\frac{4}{15}-\frac{4}{17}+...+\frac{4}{99}-\frac{4}{101}\)
\(=\frac{4}{11}-\frac{4}{101}\)
\(=\frac{360}{1111}\)
\(\dfrac{15\times27-15\times17}{10\times64-10\times54}=\dfrac{15\times\left(27-17\right)}{10\times\left(64-54\right)}=\dfrac{15}{10}=\dfrac{3}{2}\)