9/14 nhân 3/7 cộng 3/7 nhân 5/14 trừ 2/7
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LT
4
5 tháng 8 2021
\(\frac{4}{5}.\frac{3}{7}+\frac{4}{5}.\frac{6}{7}-\frac{4}{5}.\frac{4}{14}\)
\(=\frac{4}{5}.\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{14}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
MS
5
11 tháng 5 2022
=2/5(-3/7-5/14)-18/35
=2/5x(-11/14)-18/35
=-22/70-18/35=-29/35
14 tháng 4 2023
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
17 tháng 2 2019
\(\frac{3}{5}\times\frac{7}{9}+\frac{15}{18}\times\frac{2}{5}\)
\(=\frac{21}{45}+\frac{30}{90}\)
\(=\frac{4}{5}\)
#Hoktot#
N
11 tháng 9 2020
a) \(\frac{75^3.3^7}{81^4.5^6}=\frac{5^3.3^3.5^3.3^7}{\left(3^4\right)^4.5^6}=\frac{5^6.3^3.3^7}{3^{16}.5^6}=\frac{3^{10}}{3^{16}}=\frac{1}{3^6}=\frac{1}{729}\)
b) \(\frac{6^6.4^2}{3^{12}.2^8}=\frac{2^6.3^6.\left(2^2\right)^2}{3^{12}.2^8}=\frac{2^6.3^6.2^4}{3^{12}.2^8}=\frac{2^{10}.3^6}{3^{12}.2^8}=\frac{2^2.1}{3^6}=\frac{4}{729}\)
c) \(\frac{34^5.2^5}{2^{14}.17^5}=\frac{2^5.17^5.2^5}{2^{14}.17^5}=\frac{2^{10}}{2^{14}}=\frac{1}{2^4}=\frac{1}{16}\)
LN
2
Y
25 tháng 3 2023
\(\dfrac{11}{12}\times\dfrac{12}{13}\times\dfrac{13}{14}:\dfrac{22}{28}\)
\(=\dfrac{11}{12}\times\dfrac{12}{13}\times\dfrac{13}{14}\times\dfrac{14}{11}\)
\(=\dfrac{11\times12\times13\times14}{12\times13\times14\times11}\)
\(=1\)
=================
\(3\times\dfrac{7}{10}+\dfrac{7}{10}\times5+2\times\dfrac{7}{10}\)
\(=\dfrac{7}{10}\times\left(3+5+2\right)\)
\(=\dfrac{7}{10}\times10=7\)
H9
HT.Phong (9A5)
CTVHS
25 tháng 3 2023
\(\dfrac{11}{12}\times\dfrac{12}{13}\times\dfrac{13}{14}:\dfrac{22}{28}\)
\(=\dfrac{11}{12}\times\dfrac{12}{13}\times\dfrac{13}{14}:\dfrac{11}{14}\)
\(=\dfrac{11}{12}\times\dfrac{12}{13}\times\dfrac{13}{14}\times\dfrac{14}{11}\)
\(=\dfrac{11\times12\times13\times14}{12\times13\times11\times14}\)
\(=1\)
\(3\times\dfrac{7}{10}+\dfrac{7}{10}\times5+2\times\dfrac{7}{10}\)
\(=\dfrac{7}{10}\times\left(3+5+2\right)\)
\(=\dfrac{7}{10}\times10\)
\(=7\)
\(\dfrac{9}{14}\cdot\dfrac{3}{7}+\dfrac{3}{7}\cdot\dfrac{5}{14}-\dfrac{2}{7}=\dfrac{3}{7}\cdot\left(\dfrac{9}{14}+\dfrac{5}{14}\right)-\dfrac{2}{7}=\dfrac{3}{7}\cdot\dfrac{14}{14}-\dfrac{2}{7}=\dfrac{3}{7}\cdot1-\dfrac{2}{7}=\dfrac{3}{7}-\dfrac{2}{7}=\dfrac{1}{7}\)