E=1/2+1/14+1/35+...+1/209 giúp mik với ạ
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\(\Leftrightarrow A=\frac{1}{2}+\frac{1}{2\cdot7}+\frac{1}{7.5}+\frac{1}{5.13}+\frac{1}{13.8}+\frac{1}{8.19}\)
\(\Rightarrow A=\frac{1}{2}+\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{5}+\frac{1}{5}-\frac{1}{13}+\frac{1}{13}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}\)
\(\Rightarrow A=-\frac{1}{19}\)
\(a,\left(\dfrac{31}{35}-\dfrac{4}{7}\right)\times\dfrac{8}{7}:2\\ =\left(\dfrac{31}{35}-\dfrac{4\times5}{35}\right)\times\dfrac{8}{7}:2\\ =\dfrac{11}{35}\times\dfrac{8}{7}:2\\ =\dfrac{88}{245}:2\\ =\dfrac{44}{245}\\ b,\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)\\ =\left(\dfrac{2-1}{2}\right)\times\left(\dfrac{3-1}{3}\right)\times\left(\dfrac{4-1}{4}\right)\times\left(\dfrac{5-1}{5}\right)\\ =\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\\ =\dfrac{1}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\\ =\dfrac{1}{4}\times\dfrac{4}{5}=\dfrac{1}{5}\)
a, ( \(\dfrac{31}{35}\) - \(\dfrac{4}{7}\)) \(\times\) \(\dfrac{8}{7}\): 2
= \(\left(\dfrac{31}{35}-\dfrac{20}{35}\right)\) \(\times\) \(\dfrac{8}{7}\) : 2
= \(\dfrac{11}{35}\) \(\times\) \(\dfrac{8}{7}\) \(\times\) \(\dfrac{1}{2}\)
= \(\dfrac{44}{35}\) \(\times\) \(\dfrac{4}{7}\)
= \(\dfrac{44}{245}\)
b, ( 1 - \(\dfrac{1}{2}\)) \(\times\) ( 1 - \(\dfrac{1}{3}\)) \(\times\) ( 1 - \(\dfrac{1}{4}\)) \(\times\) ( 1 - \(\dfrac{1}{5}\))
= \(\dfrac{1}{2}\) \(\times\) \(\dfrac{2}{3}\) \(\times\) \(\dfrac{3}{4}\) \(\times\) \(\dfrac{4}{5}\)
= \(\dfrac{1}{5}\) \(\times\) \(\dfrac{2\times3\times4}{2\times3\times4}\)
= \(\dfrac{1}{5}\)
hellu cả lò nhà mik ạ giải giúp mik vs cả lò nhà mik ui
-5/7-(-5/67)+13/30+1/2+(-1 5/6)+1 3/14-(-2/5)
=13/30-1-5/6+2/5+17/14+1/2-5/7+5/67
=-1+17/14-3/14+5/67
=-1+1+5/67
=5/67
1) 42/35 - [ 33/14 . 21/22 - ( 54/25 : 27/25 - 7/10 )]
= 42/35 - ( 9/4-13/10)
=42/35-19/20
=1/4
2) a) 5/21 . x/34 = 35/102
x/34=35/102 : 5/21
x/34=49/34
=> x=34
Vậy x=34
b) 15/x . 21/13 = 45/91
15/x=45/91 : 21/13
15/x=15/49
=> x=49
Vậy x=49
a: \(=\dfrac{2\left(x+2\right)\left(x-1\right)}{x+2}=2x-2\)
b: \(=\dfrac{2x^3+x^2-6x^2-3x+2x+1}{2x+1}=x^2-3x+1\)
c: \(=\dfrac{x^3+2x^2-2x^2-4x+2x+4}{x+2}=x^2-2x+2\)
d: \(=\dfrac{x^2\left(x-3\right)}{x-3}=x^2\)
a, \(\dfrac{1}{2}\) - ( - \(\dfrac{1}{3}\) ) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= \(\dfrac{5}{6}\) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= 1 + \(\dfrac{1}{23}\)
= \(\dfrac{24}{23}\)
b, \(\dfrac{11}{24}\) - \(\dfrac{5}{41}\) + \(\dfrac{13}{24}\) + 0,5 - \(\dfrac{36}{41}\)
= (\(\dfrac{11}{24}\) + \(\dfrac{13}{24}\)) - ( \(\dfrac{5}{41}\) + \(\dfrac{36}{41}\)) + 0,5
= 1 - 1 + 0,5
= 0,5
c,\(-\dfrac{1}{12}-\left(\dfrac{1}{6}-\dfrac{1}{4}\right)\)
=\(-\dfrac{1}{12}-\left(-\dfrac{1}{12}\right)\)
=0
d, \(\dfrac{1}{6}-\left[\dfrac{1}{6}-\left(\dfrac{1}{4}+\dfrac{9}{12}\right)\right]\)
= \(\dfrac{1}{6}-\left[\dfrac{1}{6}-1\right]\)
= \(\dfrac{1}{6}-\left(-\dfrac{5}{6}\right)\)
= 1
1. Tính tổng:
a) (-37) + 14 + 26 + 37 = 40
b) (-24) + 6 + 10 + 24 = 16
c) 15 + 23 + (-25) + (-23) = -10
d) 60 + 33 + (-50) + (-33) = 10
e) (-16) + (-209) + (-14) + 209 = -30
f) -32 + {-54 : [(-2)8 + 7] . (-2)2} = -32 + {-54 : [(-256) + 7] . 4} = -32 + {-54 : (-249) . 4} = -32 + {-54 : (-996)} = -32 + 0 = -32
2. Thực hiện phép tính:
a) (36 + 79) + (145 - 79 - 36) = 115 + 30 = 145
b) 10 - [12 - (-9 - 1)] = 10 - [12 - (-10)] = 10 - [12 + 10] = 10 - 22 = -12
c) (38 - 29 + 43) - (43 + 38) = 52 - 81 = -29
d) 271 - [(-43) + 271 - (-17)] = 271 - [-43 + 271 + 17] = 271 - [245] = 26
3. Tính hợp lý:
a) 31 . (-18) + 31 . (-81) - 31 = -558 + (-2511) - 31 = -3100
b) (-12) . 47 + (-12) . 52 + (-12) = -564 + (-624) + (-12) = -1200
c) 13 . (23 + 22) - 3 . (17 + 28) = 13 . 45 - 3 . 45 = 585 - 135 = 450
d) -48 + 48 . (-78) + 48 . (-21) = -48 + (-3744) + (-1008) = -4800
1. Tính tổng:
a) (-37) + 14 + 26 + 37 = 40
b) (-24) + 6 + 10 + 24 = 16
c) 15 + 23 + (-25) + (-23) = -10
d) 60 + 33 + (-50) + (-33) = 10
e) (-16) + (-209) + (-14) + 209 = -30
f) -32 + {-54 : [(-2)8 + 7] . (-2)2} = -32 + {-54 : [(-256) + 7] . 4} = -32 + {-54 : (-249) . 4} = -32 + {-54 : (-996)} = -32 + 0 = -32
2. Thực hiện phép tính:
a) (36 + 79) + (145 - 79 - 36) = 115 + 30 = 145
b) 10 - [12 - (-9 - 1)] = 10 - [12 - (-10)] = 10 - [12 + 10] = 10 - 22 = -12
c) (38 - 29 + 43) - (43 + 38) = 52 - 81 = -29
d) 271 - [(-43) + 271 - (-17)] = 271 - [-43 + 271 + 17] = 271 - [245] = 26
3. Tính hợp lý:
a) 31 . (-18) + 31 . (-81) - 31 = -558 + (-2511) - 31 = -3100
b) (-12) . 47 + (-12) . 52 + (-12) = -564 + (-624) + (-12) = -1200
c) 13 . (23 + 22) - 3 . (17 + 28) = 13 . 45 - 3 . 45 = 585 - 135 = 450
d) -48 + 48 . (-78) + 48 . (-21) = -48 + (-3744) + (-1008) = -4800