Tính bằng cách thuận tiện nhất:
9/14 x 11 14/9
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\(\dfrac{14}{9}\) x \(\dfrac{11}{8}-\dfrac{3}{8}\) x \(\dfrac{14}{9}\)
\(=\dfrac{14}{9}\) x \(\left(\dfrac{11}{8}-\dfrac{3}{8}\right)\)
\(=\dfrac{14}{9}\) x \(\dfrac{8}{8}=\dfrac{14}{9}\) x \(1\)
\(=\dfrac{14}{9}\)
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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\(=\left(\dfrac{3}{8}+\dfrac{5}{14}\right)+\dfrac{26}{11}=\dfrac{1907}{616}\)
`9/14+19/18+19/14+35/18`
`=(9/14+19/14)+(19/18+35/18)`
`=28/14+54/18`
`=2+3`
`=5`
`4/6+7/13+17/9+19/13+1/9+14/6`
`=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)`
`=18/6+26/13+18/9`
`=3+2+2`
`=7`
\(\frac{14}{9}:\frac{13}{12}+\frac{4}{3}:\frac{13}{12}\)
\(=\frac{14}{9}\cdot\frac{12}{13}+\frac{4}{3}\cdot\frac{12}{13}\)
\(=\left(\frac{14}{9}+\frac{4}{3}\right)\cdot\frac{12}{13}\)
\(=\frac{26}{9}\cdot\frac{12}{13}=\frac{8}{3}\)
\(\dfrac{3}{7}\cdot\dfrac{9}{26}-\dfrac{1}{14}\cdot\dfrac{1}{13}\)
\(=\dfrac{3\cdot9-1}{14\cdot13}=\dfrac{26}{14\cdot13}=\dfrac{2}{14}=\dfrac{1}{7}\)
x đúng ko
\(\dfrac{9}{14}x11x\dfrac{14}{9}=\left(\dfrac{9}{14}x\dfrac{14}{9}\right)x11=1x11=11\)