Tìm x : ( \(\frac{3}{5}\))x = ( \(\frac{9}{25}\) )4
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11 tháng 9 2020
\(a.\left(x-1\right)^2=\frac{9}{25}\)
\(\left(x-1\right)^2=\left(\frac{3}{5}\right)^2\)
\(x-1=\frac{3}{5}\)
\(x=\frac{3}{5}+1\)
\(x=\frac{8}{5}\)
\(b.\frac{1}{2}-\frac{1}{3}.x=\frac{4}{5}\)
\(\frac{1}{3}.x=\frac{1}{2}-\frac{4}{5}\)
\(\frac{1}{3}.x=\frac{-3}{10}\)
\(x=\frac{-3}{10}:\frac{1}{3}\)
\(x=\frac{-3}{10}.\frac{3}{1}\)
\(x=\frac{-9}{10}\)
11 tháng 9 2020
a) \(\left(x-1\right)^2=\frac{9}{25}\)
\(\left(x-1\right)^2=\left(\frac{3}{5}\right)^2\)
\(TH1:x-1=\frac{3}{5}\Rightarrow x=\frac{8}{5}\)
\(TH2:x-1=-\frac{3}{5}\Rightarrow-\frac{3}{5}+1=\frac{2}{5}\)
\(\Rightarrow x\in\left\{\frac{8}{5};\frac{2}{5}\right\}\)
b) \(\frac{1}{2}-\frac{1}{3}x=\frac{4}{5}\)
\(\frac{1}{3}x=\frac{1}{2}-\frac{4}{5}=-\frac{3}{10}\)
\(x=-\frac{3}{10}:\frac{1}{3}\)
\(x=-\frac{9}{10}\)
9 tháng 3 2018
a) \(x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{2}{25}\)
b) \(x=\frac{5}{11}+\frac{4}{-9}=\frac{45}{99}+\frac{-44}{99}=\frac{1}{99}\)
c) \(\frac{5}{9}+\frac{x}{-1}=\frac{-1}{3}\)
\(\Rightarrow\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}\)
\(\Rightarrow\frac{x}{-1}=\frac{-8}{9}\)
\(\Rightarrow x=\frac{\left(-8\right).\left(-1\right)}{9}=\frac{8}{9}\)
XO
1 tháng 8 2020
Ta có \(\frac{9}{25}x+\frac{3}{5}.\frac{9}{25}x+\frac{3}{5}.18+\frac{9}{25}x+18=x\)
=> \(\frac{9}{25}x\left(1+\frac{3}{5}+1\right)+18\left(\frac{3}{5}+1\right)=x\)
=> \(\frac{117}{125}x+28,8=x\)
=> \(x-\frac{117}{125}x=28,8\)
=> \(\frac{8}{125}x=28,8\)
=> x = 450
Vậy x = 450
1 tháng 8 2020
\(\frac{9}{25}x+\frac{3}{5}.\frac{9}{25}x+\frac{3}{5}.18+\frac{9}{25}x+18=x\)
\(x\left(\frac{9}{25}+\frac{9}{25}+\frac{9}{25}\right).\frac{3}{5}+\frac{3}{5}.18+18=x\)
\(x.\frac{3}{5}\left(\frac{27}{25}+18\right)+18=x\)
\(x.\frac{3}{5}\left(\frac{27}{25}+\frac{450}{25}\right)+18=x\)
\(x.\frac{3}{5}.\frac{477}{25}+18=x\)
\(x.\frac{1431}{125}+\frac{2250}{125}=x\)
\(x.\frac{3681}{125}=x\)
vậy chac tui làm sai rồi
\(\left(\frac{3}{5}\right)^x=\left(\frac{9}{25}\right)^4\)
\(\Leftrightarrow\left(\frac{3}{5}\right)^x=\left[\left(\frac{3}{5}\right)^2\right]^4\)
\(\Leftrightarrow\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^8\)
\(\Leftrightarrow x=8\)
(3/5)x=(9/25)4
=> (3/5)x=[(3/5)2 ]4
=> (3/5)x=(3/5)2.4
=> x=2.4
=> x=8