Question

[Trần Long]

 

Answer 1

[Nguyễn Lê Phước Thịnh]

\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{3}{4}\right)< =x< =\dfrac{1}{24}-\left(\dfrac{1}{8}-\dfrac{1}{3}\right)\)

=>\(\dfrac{1}{2}-\dfrac{4+9}{12}< =x< =\dfrac{1}{24}-\dfrac{3-8}{24}\)

=>\(\dfrac{1}{2}-\dfrac{13}{12}< =x< =\dfrac{1-\left(-5\right)}{24}\)

=>\(\dfrac{-7}{12}< =x< =\dfrac{6}{24}\)

=>\(\dfrac{-7}{12}< =x< =\dfrac{1}{4}\)

mà x nguyên

nên x=0