sos 3/5+9/5:1/5
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\(=\left(\dfrac{5}{7}+\dfrac{9}{7}\right)\times\dfrac{3}{2}=2\times\dfrac{3}{2}=3\)
\(=\dfrac{4}{5}\times\left(6+1+3\right)=\dfrac{4}{5}\times10=\dfrac{40}{5}=8\)
a) 5/7 x 3/2 + 3/2 x 9/7
= (5/7 + 9/7) x 3/2
= 2 x 3/2
= 6/2 = 3
b) 4/5 + 4/5 x 6 + 3 x 4/5
= 4/5 x 1 + 4/5 x 6 + 3 x 4/5
= 4/5 x (1 + 6 + 3)
= 4/5 x 10
= 40/5 = 8
`3/5+2/5:x=1 1/10`
`3/5+2/5:x=11/10`
`2/5:x=11/10-3/5=1/2`
`x=2/5:1/2=4/5`
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`(x-3/5)xx3/8-5/8=1/6`
`(x-3/5)xx3/8=1/6+5/8`
`(x-3/5)xx3/8=4/24+15/24=19/24`
`x-3/5=19/24:3/8=19/9`
`x=19/9+3/5=122/45`
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`1 1/6-5/6:(x+1/4)=1/2`
`7/6-5/6:(x+1/4)=1/2`
`5/6:(x+1/4)=7/6-1/2=2/3`
`x+1/4=5/6:2/3=5/4`
`x=5/4-1/4=4/4=1`
C=(1-5-9+13)+(17-21-25+29)+...+(2013-2017-2021+2025)-2029
C=0+0+0+...+0-2029
C=-2029
C = 1 - 5 - 9 + 13 + 17 - 21 - 25 + 29 + ... + 2013 - 2017 - 2021 + 2025 - 2029
= (1 - 5 - 9 + 13) + (17 - 21 - 25 + 29) + ... + (2001 - 2005 - 2009 + 2013) - 2017 - 2021 + 2025 - 2029
= 0 + 0 + ... + 0 - 4042
= -4042
Lời giải:
$A=-x.24.(-6)-18.5:y=-(-3).24(-6)-18.5:(-9)=-432-(-10)=-432+10=-(432-10)=-422$
3/5+4/6=3/5+2/3=9/15+10/15=19/15
7-1/3=20/3
5x3/8=15/8
12/35:2/5=12/35x5/2=60/70=6/7
\(\dfrac{3}{5}+\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{2}{3}=\dfrac{19}{15}\)
\(7-\dfrac{1}{3}=\dfrac{20}{3}\)
\(5x\dfrac{3}{8}=\dfrac{15}{8}\)
\(\dfrac{12}{35}:\dfrac{2}{5}=\dfrac{12}{35}x\dfrac{5}{2}=\dfrac{6}{7}\)
\(1,\left[\left(-\dfrac{2}{5}\right)+\dfrac{1}{3}\right]-\left(\dfrac{3}{5}-\dfrac{1}{3}\right)=-\dfrac{2}{5}+\dfrac{1}{3}-\dfrac{3}{5}+\dfrac{1}{3}\\ =\left(-\dfrac{2}{5}-\dfrac{3}{5}\right)+\left(\dfrac{1}{3}+\dfrac{1}{3}\right)\\ =\dfrac{-2-3}{5}+\dfrac{1+1}{3}\\ =-\dfrac{5}{5}+\dfrac{2}{3}\\ =-1+\dfrac{2}{3}\\ =\dfrac{-3+2}{3}=-\dfrac{1}{3}\\ b,\left(\dfrac{3}{2}-\dfrac{3}{4}\right)-\left(0,25+\dfrac{1}{2}\right)\\ =\left(\dfrac{3}{2}-\dfrac{3}{4}\right)-\left(\dfrac{1}{4}+\dfrac{1}{2}\right)\\ =\dfrac{3}{2}-\dfrac{3}{4}-\dfrac{1}{4}-\dfrac{1}{2}\\ =\left(\dfrac{3}{2}-\dfrac{1}{2}\right)+\left(-\dfrac{3}{4}-\dfrac{1}{4}\right)\\ =\dfrac{3-1}{2}+\dfrac{-3-1}{4}\\ =\dfrac{2}{2}-\dfrac{4}{4}=1-1=0\)
1: =-2/5+1/3-3/5+1/3
=-1+2/3=-1/3
2: =3/2-3/4-1/4-1/2
=1-1=0
`(-3/4)+(-1/4)+2/7+5/7+3/5`
`=[(-3/4)+(-1/4)]+(2/7+5/7)+3/5`
`=-4/4+7/7+3/5`
`=-1+1+3/5`
`=0+3/5`
`=3/5`
-3/4 + -1/4 + 2/7 + 5/7 + 3/5
= (-3/4 + -1/4) + (2/7 + 5/7) + 3/5
= (-1 + 1) + 3/5
= 0 + 3/5
= 0
\(\dfrac{x}{-5}=\dfrac{y}{9}=\dfrac{z}{11}\) và \(x-z=-32\)
Ta có\(\dfrac{x}{-5}=\dfrac{z}{11}=\dfrac{x-z}{-5-11}=-\dfrac{32}{-16}=2\)
\(\left\{{}\begin{matrix}x=2\cdot\left(-5\right)=-10\\y=2\cdot9=18\\z=2\cdot11=22\end{matrix}\right.\)
Vậy x=-10
y=18
z=22
\(\dfrac{3}{5}+\dfrac{9}{5}:\dfrac{1}{5}=\dfrac{3}{5}+9=\dfrac{9\cdot5+3}{5}=\dfrac{48}{5}\)
3/5 + 9/5 : 1/5 = 3/5 + 9 = 9 • 5 + 3/5 = 48/5