Viết tích 32×243 dưới dạng lũy thừa của một số?
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a: \(A=\left(2^3\right)^2\cdot\left(2^5\right)^4=2^6\cdot2^{20}=2^{26}\)
b: \(=\left(3^3\right)^3\cdot\left(3^2\right)^4\cdot3^5=3^9\cdot3^8\cdot3^5=3^{22}\)
\(A=8^2.32^4=\left(2^3\right)^2.\left(2^5\right)^4=2^6.2^{20}=2^{26}\)
\(B=27^3.9^4.243=\left(3^3\right)^3.\left(3^2\right)^4.3^5=3^9.3^8.3^5=3^{22}\)
a: \(A=8^2\cdot32^4=2^6\cdot2^{20}=2^{26}\)
b: \(B=27^3\cdot9^4\cdot243=3^9\cdot3^8\cdot3^5=3^{22}\)
\(\frac{-32}{243}=\frac{-4\cdot8}{3\cdot81}=\frac{-2^2\cdot2^3}{3\cdot3^4}=\frac{-2^5}{3^5}\)
\(8^2.32^4=2^{3.2}.2^{5.4}=2^6.2^{20}=2^{20+6}=20^{26}\)
\(27^3.9^4.243=3^{3.3}.9^{2.4}.3^5=3^9.3^8.3^5=3^{9+8+5}=3^{22}\)
\(8^2\cdot32^4=\left(2^3\right)^2\cdot\left(2^5\right)^4=2^6\cdot2^{20}=2^{26}\)
\(27^3\cdot9^4\cdot243=\left(3^3\right)^3\cdot\left(3^2\right)^4\cdot3^5=3^9\cdot3^8\cdot3^5=3^{22}\)
\(A=8^2.32^4=2^6.2^{20}=2^{26}\)
\(\Rightarrow2^{26}\)
\(B=27^3.9^4.243=3^9.3^8.3^5=3^{22}\)
\(\Rightarrow3^{22}\)
TL
a . x ∈ ∅ b . x=-10, x=-5177/5000, x=-10173/10000.
HT
a ) \(A=8^2.32^4=\left(2^3\right)^2.\left(2^5\right)^4\)
\(=2^6.2^{20}\)
\(2^{6+20}=2^{26}\)
b ) \(B=27^3.9^4.243=\left(3^3\right)^3.\left(3^2\right)^4.3^5\)
\(=3^9.3^8.3^5=3^{9+8+5}\)
\(=3^{22}\)
a) A= 8^2 . 32^4
= (23)2 . (25)4
= 2^6 . 2^20 = 2^26
b) B= 27^3 . 9^4 . 243
= (3^3)^3 . (3^2)^4 . 3^5
= 3^9 . 3^8 . 3^5
=3^22
\(32\times243=2^5\times3^5=6^5\)
32x243=7776=2^5x3^5=(2+3)^5=6^5