[55+11(x-4)]:17=22
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Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{7}{3\cdot3}\cdot\dfrac{3}{7\cdot5}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9}{11\cdot2}\cdot11\cdot5=\dfrac{45}{2}\)
\(\dfrac{11}{17}:\dfrac{33}{34}=\dfrac{11}{17}\cdot\dfrac{34}{33}=\dfrac{11\cdot17\cdot2}{17\cdot11\cdot3}=\dfrac{2}{3}\)
\(\dfrac{93}{17}:x+\left[\dfrac{-4}{17}\right]:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}\)
\(=>\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(=>\dfrac{89}{17}:x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(=>\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{11}{26}\)
\(=>\dfrac{89}{17}:x=\dfrac{-17}{286}\)
\(=>x=\dfrac{89}{17}:\dfrac{-17}{286}\)
\(=>x=\dfrac{-25454}{289}=-88\dfrac{22}{289}\)
(93/17+-4/17) : x + 33/182=4/11
89/17 : x = 4/11 + 33/182
89/17 : x = Sia đề
11x11=121
22x22=484
33x33=1089
44x44=1936
55x55=3025
66x66=4356
k mk nhé,1000000% đúng
[55+11(x-4)] : 17 = 22
[55+11(x-4)] = 22 . 17
[55+11(x-4)] = 374
11(x-4) = 374-55
11(x-4) = 319
x-4 = 319 : 11
x-4 = 29
x = 29+4
x = 33