(7.x-11)3=25.55+200
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`-75.57 + 75.34 - ( 57.34 - 57.75 )`
`= -75 . 57 + 75.34 - 57.34 + 57.75`
`= 75.( - 57 + 34 + 57) + 75.34`
`= 75.34 + 75.34`
`= (75.34) .2`
`= 2550 . 2`
`= 5100`
_______
\(-11.45 - (-11).25 - ( 29.3+29.17 )\)
`= -11. (45 - 25) - 29(3 + 17)`
`= -11.20 - 29.20`
`= 20. (-11 - 29)`
`= 20. (-40)`
`= -80`
_______
\(-12.7 -72.(-12) - ( 25.55-25.43 )\)
`= -12. (7 - 72) - 25( 55 - 43)`
`= -12.(-65) - 25.12`
`= 12.65 - 25 . 12`
`= 12(65 - 25)`
`= 12.40`
`= 480`
Thế này mới đúng
\(\left(7x-11\right)^3=2^5.5^26+200\)
= \(\left(7x-11\right)^3=1000\)
= \(\left(7x-11\right)^3=10^3\)
= \(\left(7x-11\right)=10\)
= \(7x=10+11\)
= \(7x=21\)
=> \(x=21:7\)
=> x = 3
Bạn thử vào x chắc chắn đúng 99,9%
= \(\left(7.x-11\right)^3=1000\)
= \(\left(7.x\right)^3=1000+11=1011\)
= \(\left(7.x\right)^3=1011\)
= \(1011:7=\frac{1011}{7}\)
= \(x^3=\frac{1011}{7}=1,433790434\)
a, 2x = 17 + 15
2x = 32
2x = 25
=> x = 5
b, ( 7. x - 11 )3 = 25 . 52 + 200
( 7 . x - 11 )3 = 32 . 25 + 200
( 7 . x - 11 )3 = 800 + 200
( 7 . x - 11 )3 = 1000
( 7 . x - 11 )3 = 103
7 . x - 11 = 10
7 . x = 10 + 11
7 . x = 21
x = 21 : 7
x = 3
\(2^x\)-15=17
\(\Rightarrow\)\(2^x\)=17+15
\(\Rightarrow2^x\)=32
Vì \(2^6\)=32
\(\Rightarrow\)x=6
(7.x-11)^3=2^5.5^2+200
(7.x-11)^3=16.25+200
(7.x-11)^3=600
Xong bạn tìm số có có lập phương bằng 600 thế chắc là bạn tính dc rồi nhỉ!!!!!!!
có j kb vs mik ,mik hướng dẫn thêm cho
\(a,210-5\left(x-11\right)=200\\ \Rightarrow5\left(x-11\right)=10\\ \Rightarrow x-11=2\\ \Rightarrow x=13.\\ b,\left(2x+1\right):7=2^2+3^2\\ \Rightarrow\left(2x+1\right):7=4+9\\ \Rightarrow\left(2x+1\right):7=13\\ \Rightarrow2x+1=91\\ \Rightarrow2x=90\\ \Rightarrow x=45.\\ c,450:\left[41-\left(2x-5\right)\right]=3^2.5\\ \Rightarrow450:\left[41-\left(2x-5\right)\right]=45\\ \Rightarrow41-\left(2x-5\right)=10\\ \Rightarrow2x-5=31\\ \Rightarrow2x=36\\ \Rightarrow x=18.\\ d,\left(5x-9\right).7+3=80\\ \Rightarrow\left(5x-9\right).7=77\\ \Rightarrow5x-9=11\\ \Rightarrow5x=20\\ \Rightarrow x=4.\)
a) \(210-5\left(x-11\right)=200\)
\(5.\left(x-11\right)=210-200\)
\(5.\left(x-11\right)=10\)
\(x-11=10:5\)
\(x-11=2\)
\(x=2+11\)
\(x=13\)
b) \(\left(2x+1\right):7=2^2+3^2\)
\(\left(2x+1\right):7=13\)
\(2x+1=13.7\)
\(2x=91-1\)
\(2x=90\)
\(x=90:2\)
\(x=45\)
c) \(450:\left[41-\left(2x-5\right)\right]=3^2.5\)
\(450:\left[41-\left(2x-5\right)\right]=45\)
\(\left[41-\left(2x-5\right)\right]=450:45\)
\(\left[41-\left(2x-5\right)\right]=10\)
\(2x-5=41-10\)
\(2x-5=31\)
\(2x=31+5\)
\(2x=36\)
\(x=36:2\)
\(x=18\)
d) \(\left(5x-9\right).7+3=80\)
\(\left(5x-9\right).7=80-3\)
\(5x-9=77:7\)
\(5x-9=11\)
\(5x=11+9\)
\(5x=20\)
\(x=20:5\)
\(x=4\)
\(\left(7x-11\right)^3=2^5\cdot5^5+200\)
=>\(\left(7x-11\right)^3=10^5+200=100200\)
=>\(7x-11=\sqrt[3]{100200}\)
=>\(7x=11+\sqrt[3]{100200}\)
=>\(x=\dfrac{11+\sqrt[3]{100200}}{7}\)