Tìm x:
\(\frac{72-x}{7}\)- \(\frac{x-70}{9}\)
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a/ x:0,16 = 9:x hay \(\frac{x}{0,16}=\frac{9}{x}\)
=>x.x=0,16.9
=>x2=1,44
=>x2=(1,2)2
=>x=1,2 hoặc x=-1,2
b)\(\frac{72-x}{7}=\frac{x-10}{9}\)
=>(72-x).9=7.(x-10)
648-9x=7x-70
-9x-7x=-70-648
-16x=-718
x=44,875
a) x: 0,16 =9:x hay \(\frac{x}{0,16}\)=\(\frac{9}{x}\)
\(\Rightarrow\)x.x= 0,16.9
\(\Rightarrow\)\(^{x^2}\)=1,44
\(\Rightarrow\)\(^{x^2}\)= \(^{\left(1.2\right)^2}\)
\(\Rightarrow\)x=1,2 hoặc -1,2.
b) \(\frac{72-x}{7}\)= \(\frac{x-10}{9}\)
\(\Rightarrow\)(72-x).9 = 7.(x-10)
648-9x=7x-70
-9x - 7x=-70-648
-16x=-718
\(\Rightarrow\)x= 44,875.
<=> (x-18/74 - 1)+(x-20/72 - 1)+(x-22/70 - 1) = 0
<=> x-92/74 + x-92/72 + x-92/70 = 0
<=> (x-92).(1/74+1/72+1/70) = 0
<=> x-92 = 0 ( vì 1/74 + 1/72 + 1/70 > 0 )
<=> x=92
Vậy S = {92}
Tk mk nha
Ta có :
\(\frac{x-18}{74}+\frac{x-20}{72}+\frac{x-22}{70}=3\)
\(\Leftrightarrow\)\(\left(\frac{x-18}{74}-1\right)+\left(\frac{x-20}{72}-1\right)+\left(\frac{x-22}{70}-1\right)=3-3\)
\(\Leftrightarrow\)\(\frac{x-92}{74}+\frac{x-92}{72}+\frac{x-92}{70}=0\)
\(\Leftrightarrow\)\(\left(x-92\right)\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)=0\)
Vì \(\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)\ne0\)
\(\Rightarrow\)\(x-92=0\)
\(\Rightarrow\)\(x=92\)
Vậy \(x=92\)
Chúc bạn học tốt
\(\text{Cách 1:}\)
\(\frac{72-x}{7}=\frac{x-40}{9}\)
=> \(\left(72-x\right)\cdot9=\left(x-40\right)\cdot7\)
=> \(648-9x=7x-280\)
=> \(648+280=7x+9x\)
=> \(16x=928\)=> \(x=928:16=58\)
\(\text{Cách 2:}\)
\(\text{Áp dụng tính chất dãy tỉ số bằng nhau, ta có:}\)
\(\frac{72-x}{7}=\frac{x-40}{9}=\frac{72-x+x-40}{7+9}=\frac{32}{16}=2\)
\(\text{Ta suy ra:}\)
\(\frac{72-x}{7}=2\)=> \(72-x=2\cdot7=14\)=> \(x=72-14=58\)
\(\text{Vậy }x=58\)
a) \(\frac{x}{6}^2=\frac{24}{25}\)
\(\Rightarrow x^2.25=6.24\)
\(\Rightarrow x^2.25=144\)
\(\Rightarrow x^2=144\div25\)
\(\Rightarrow x^2=5,76=2,4^2=\left(-2,4^2\right)\)
\(\Rightarrow x\in\left\{2,4;-2,4\right\}\)
Vậy \(x\in\left\{2,4;-2,4\right\}\)
b) \(\frac{72-x}{7}=\frac{x-40}{9}\)
\(\Rightarrow\left(72-x\right).9=\left(x-40\right).7\)
\(\Rightarrow648-9x=7x-280\)
\(\Rightarrow\left(-280\right)-648\) \(=-9x-7x\)
\(\Rightarrow-928=-16x\)
\(\Rightarrow x=58\)
Vậy \(x=58\)
ta có:
\(\left(7\frac{1}{2}.8\frac{3}{70}+8\frac{3}{70}.\frac{9}{4}+\frac{19}{4}.8\frac{3}{70}+5\frac{1}{2}.8\frac{3}{70}\right):x=1126\)
\(8\frac{3}{70}\left(7\frac{1}{2}+\frac{9}{4}+\frac{19}{4}+5\frac{1}{2}\right):x=1126\)
\(\frac{563}{70}.\left(\frac{15}{2}+7+\frac{11}{2}\right):x=1126\)
\(\frac{563}{70}.20:x=1126\)
\(\frac{1126}{70}:x=1126\)
\(=>x=\frac{1126}{7}:1126\)
\(=>x=\frac{1}{7}\)
cho mình nha các bạn.
\(\frac{x-18}{74}+\frac{x-20}{72}+\frac{x-22}{70}=3\)
\(\Leftrightarrow\)\(\left(\frac{x-18}{74}-1\right)+\left(\frac{x-20}{72}-1\right)+\left(\frac{x-22}{70}-1\right)=0\)
\(\Leftrightarrow\)\(\frac{x-92}{74}+\frac{x-92}{72}+\frac{x-92}{70}=0\)
\(\Leftrightarrow\)\(\left(x-92\right)\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)=0\)
Mà \(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\ne0\)
\(\Leftrightarrow\)\(x+92=0\)
\(\Leftrightarrow\)\(x=-92\)
Vậy S = { - 92 }
Ta có :
\(\frac{x-18}{74}+\frac{x-20}{72}+\frac{x-22}{70}=3\)
\(\Leftrightarrow\)\(\left(\frac{x-18}{74}-1\right)+\left(\frac{x-20}{72}-1\right)+\left(\frac{x-22}{70}-1\right)=3-3\)
\(\Leftrightarrow\)\(\frac{x-92}{74}+\frac{x-92}{72}+\frac{x-92}{70}=0\)
\(\Leftrightarrow\)\(\left(x-92\right)\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)=0\)
Vì \(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\ne0\)
\(\Rightarrow\)\(x-92=0\)
\(x=92\)
Vậy \(x=92\)
Chúc bạn học tốt
Ap dung tinh chat day ti so bang nhau Ta co :
\(\frac{x}{9}=\frac{z}{7}=\frac{y}{8}=\frac{t}{6}=\frac{y-t}{8-6}=\frac{70}{2}=35\)
Suy ra x= 35 . 9 =315
z =35.7=245
y = 35.8=280
t=280-70=210
Vay x=315,y=280,z=245,t=210
Chuc ban hoc tot
Áp dunhj tính chất của dãy tỉ số bằng nhau ta có :
\(\frac{x}{9}=\frac{y}{8}=\frac{z}{7}=\frac{7}{6}=\frac{y-7}{8-6}=\frac{70}{2}=35\)
\(\Rightarrow\frac{x}{9}=35\Rightarrow x=315\)
\(\frac{y}{8}=35\Rightarrow y=280\)
\(\frac{z}{7}=35\Rightarrow z=245\)
\(\frac{t}{6}=35\Rightarrow t=210\)
Study well
72-x nhân9 - x -70 nhân7
= 648 - 9x - 7x-490
=158-2x
Ta có \(\frac{72-x}{7}-\frac{x-70}{9}=\frac{\left(72-x\right).9}{7.9}-\frac{\left(x-70\right).7}{9.7}=\frac{648-9x}{63}-\frac{7x-490}{63}\)
\(=\frac{648-9x-7x-490}{63}=\frac{158-2x}{63}\)