Question

[Hà Trí Kiên]

Tìm x trong các tỉ lệ thức sau

x-1/33 = 4/x

Giúp với mình cần gấp

Answer 1

[HT.Phong (9A5)]

\(\dfrac{x-1}{33}=\dfrac{4}{x}\left(x\ne0\right)\)

\(\Rightarrow x\left(x-1\right)=4\cdot33\)

\(\Rightarrow x^2-x=132\)

\(\Rightarrow x^2-x=132\)

\(\Rightarrow x^2-12x+11x-132=0\)

\(\Rightarrow x\left(x-12\right)+11\left(x-12\right)=0\)

\(\Rightarrow\left(x-12\right)\left(x+11\right)=0\)

TH1: \(x-12=0\Rightarrow x=12\left(tm\right)\)

TH2: \(x+11=0\Rightarrow x=-11\left(tm\right)\)

Answer 2

[Citii?]

\(\left\{{}\begin{matrix}x=12\\x=-11\end{matrix}\right.\)