Question

[Nguyễn Thanh Huyền]

cần giúp trừ phần u đc ko ạ

Answer 1

[Nguyễn Lê Phước Thịnh]

v: \(\dfrac{26}{-37}< 0\)

\(0< \dfrac{11}{19}\)

Do đó: \(\dfrac{26}{-37}< \dfrac{11}{19}\)

x: \(\dfrac{-7}{30}=\dfrac{-7\cdot2}{30\cdot2}=\dfrac{-14}{60}\)

\(\dfrac{13}{-20}=\dfrac{-13}{20}=\dfrac{-13\cdot3}{20\cdot3}=\dfrac{-39}{60}\)

mà -14>-39

nên \(-\dfrac{7}{30}< \dfrac{13}{-20}\)

y: \(-\dfrac{12}{16}=\dfrac{-12\cdot3}{16\cdot3}=\dfrac{-36}{48}\)

\(\dfrac{-16}{48}=\dfrac{-16}{48}\)

mà -36<-16

nên \(\dfrac{-12}{16}< -\dfrac{16}{48}\)

z: \(\dfrac{-18}{-72}=\dfrac{1}{4}>0\)

\(0>-\dfrac{5}{20}\)

Do đó: \(\dfrac{-18}{-72}>-\dfrac{5}{20}\)

z1: \(\dfrac{-36}{90}=\dfrac{-2}{5};\dfrac{-15}{25}=\dfrac{-3}{5}\)

mà -2>-3

nên \(\dfrac{-36}{90}>\dfrac{-15}{25}\)

z2: \(\dfrac{-32}{48}=\dfrac{-2}{3}=\dfrac{-4}{6}\)

\(\dfrac{-6}{12}=\dfrac{-1}{2}=\dfrac{-3}{6}\)

mà -4<-3

nên \(-\dfrac{32}{48}< -\dfrac{6}{12}\)

z3: \(\dfrac{-20}{-45}=\dfrac{4}{9}=\dfrac{40}{90}\)

\(\dfrac{35}{150}=\dfrac{7}{30}=\dfrac{21}{90}\)

mà 40>21

nên \(\dfrac{-20}{-45}>\dfrac{35}{150}\)