7/5 x 4/3 x 4/3
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\(5-\left(6-x\right)=4\left(3-2x\right)\)
\(5-6+x=12-8x\)
\(-1+x=12-8x\)
\(x-1=12-8x\)
\(12+1=8x+1\)
\(8x=13-1\)
\(x=12:8\)
\(x=\dfrac{12}{8}=\dfrac{3}{2}\)
\(PT\Leftrightarrow5-6+x=12-8x\)
\(\Leftrightarrow9x=13\)
\(\Leftrightarrow x=\dfrac{13}{9}\)
Vậy: \(S=\left\{\dfrac{13}{9}\right\}\)
\(\frac{3}{4}+\frac{1}{4}\cdot x+x-\frac{7}{6}\cdot x=\frac{5}{12}\)
\(\frac{3}{4}+\frac{1}{4}\cdot x-\frac{7}{6}\cdot x+x\cdot1=\frac{5}{12}\)
\(\frac{3}{4}+x\left(\frac{1}{4}-\frac{7}{6}+1\right)=\frac{5}{12}\)
\(\frac{3}{4}+x\cdot\frac{1}{12}=\frac{5}{12}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{3}{4}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{9}{12}\)
\(x\cdot\frac{1}{12}=\frac{-1}{3}\)
\(x=\frac{-1}{3}\text{ : }\frac{1}{12}\)
\(x=\frac{-1}{3}\cdot12\)
\(x=\frac{-12}{3}\)
\(x=-4\)
\(\text{b, }0,25\cdot x-\frac{2}{3}\cdot x=-1\frac{1}{6}\)
\(\frac{1}{4}\cdot x-\frac{2}{3}\cdot x=\frac{-7}{6}\)
\(x\cdot\left(\frac{1}{4}-\frac{2}{3}\right)=\frac{-7}{6}\)
\(x\cdot\frac{-5}{12}=\frac{-7}{6}\)
\(x=\frac{-7}{6}\text{ : }\frac{-5}{12}\)
\(x=\frac{-7}{6}\cdot\frac{12}{-5}\)
\(x=\frac{-14}{-5}\)
\(\frac{4}{7}x-\frac{2}{3}=\frac{1}{5}\)
\(\Leftrightarrow\frac{4}{7}x=\frac{1}{5}+\frac{2}{3}\)
\(\Leftrightarrow\frac{4}{7}x=\frac{3}{15}+\frac{10}{15}\)
\(\Leftrightarrow\frac{4}{7}x=\frac{13}{15}\)
\(\Leftrightarrow x=\frac{13}{15}:\frac{4}{7}=\frac{13}{15}\cdot\frac{7}{4}=\frac{91}{60}\)
\(\dfrac{7}{3}.\dfrac{-5}{2}.\dfrac{15}{21}.\dfrac{-4}{5}=-\dfrac{46}{630}=-\dfrac{23}{315}\)
\(\dfrac{20\times25\times7\times8}{75\times8\times12\times14}\)
= \(\dfrac{4\times5\times25\times7\times8}{3\times25\times8\times3\times4\times2\times7}\)
= \(\dfrac{25\times7\times8\times4\times5}{25\times7\times8\times4\times2\times3\times3}\)
= \(\dfrac{25\times7\times8\times4}{25\times7\times8\times4}\) x \(\dfrac{5}{2\times3\times3}\)
= 1 x \(\dfrac{5}{18}\)
= \(\dfrac{5}{18}\)
\(=\dfrac{5.4.5.5.7.8}{5.3.5.8.7.4}\)
Triệt tiêu những phần giống nhau của cả tử và mẫu ta có:
\(=\dfrac{5}{3}\)
\(\dfrac{7}{5}\times\dfrac{4}{3}\times\dfrac{4}{3}\)
\(=\dfrac{28}{15}\times\dfrac{4}{3}\)
\(=\dfrac{112}{45}\)
\(\dfrac{7}{5}\times\dfrac{4}{3}\times\dfrac{4}{3}=\dfrac{28}{15}\times\dfrac{4}{3}=\dfrac{28\times4}{15\times3}=\dfrac{112}{45}\)