phân tích thanh nhân từ x ( x + y ) - 5x - 5y
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x(x + y) – 5x – 5y
= x( x+ y) – ( 5x + 5y)
= x(x + y) – 5(x + y) = (x + y)(x – 5)
\(y\cdot\left(x-y\right)-5x+5y=y\cdot\left(x-y\right)-5\cdot\left(x-y\right)=\left(x-y\right)\cdot\left(y-5\right)\)
\(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\)
\(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x+y-5\right)\left(x-y\right)\)
a, \(\left(3x-6y\right)x+y\left(x-2y\right)=\left(3x+y\right)\left(x-2y\right)\)
b, \(3\left(x-y\right)-5x\left(y-x\right)=\left(3+5x\right)\left(x-y\right)\)
c, \(\dfrac{2}{5}x\left(y-1\right)+\dfrac{2}{5}y\left(1-y\right)=\left(\dfrac{2}{5}x-\dfrac{2}{5}y\right)\left(y-1\right)=\dfrac{2}{5}\left(x-y\right)\left(y-1\right)\)
d, \(x\left(x-1\right)-y\left(1-x\right)=\left(x+y\right)\left(x-1\right)\)
\(=\left(x-y\right)\left(x+y\right)+5\left(x-y\right)\)
\(=\left(x+y+5\right)\left(x-y\right)\)
Học tốt
b ) 5 x ( x - 1 ) - 3x ( x - 1 )
= ( 5x - 3x ) ( x - 1 )
= 2x ( x - 1 )
c ) x ( x + y ) - 5 x - 5y
= x ( x + y ) - 5 ( x + y )
= ( x - 5 ) (x + y )
d ) x ^ 2 + xy + x
= x ( x + y + 1 )
e ) x ( x - y ) + y ( y - x )
= x ( x - y ) - y ( x - y )
= ( x - y ) ( x -y )
= ( x - y ) 2
x(x+y)-5x-5y
= \(x^2+xy-5x-5y\)
\(=\left(x^2-5x\right)+\left(xy-5y\right)\)
\(=x\left(x-5\right)+y\left(x-5\right)\)
\(=\left(x-5\right)\left(x+y\right)\)