Chuyển các hỗn số sau thành số thập phân rồi tính:
\(98\frac{23}{313}+33\frac{67}{124}-11\frac{23}{109}\times88\frac{93}{165}\div10\frac{57}{808}\)=?
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\(\frac{31}{4}=7\frac{3}{4}\)
\(\frac{25}{3}=8\frac{1}{3}\)
\(\frac{36}{5}=7\frac{1}{5}\)
\(\frac{78}{21}=3\frac{5}{7}\)
\(\frac{65}{23}=2\frac{19}{23}\)
\(4\frac{2}{3}+2\frac{3}{4}.7\frac{3}{11}=\frac{14}{3}+\frac{11}{4}.\frac{80}{11}=\frac{14}{3}+20=\frac{14}{3}+\frac{60}{3}=\frac{74}{3}\)
\(4\frac{2}{3}+2\frac{3}{4}\times7\frac{3}{11}\)
\(=\frac{14}{3}+\frac{11}{4}\times\frac{80}{11}\)
\(=\frac{14}{3}+\frac{11\times80}{4\times11}\)
\(=\frac{14}{3}+20\)
\(=\frac{14}{3}+\frac{60}{3}\)
\(=\frac{74}{3}\)
\(\begin{array}{l}\frac{{ - 3519}}{{100}} = - 35,19;\,\,\,\frac{{ - 778}}{{10}} = - 77,8;\\\,\,\frac{{ - 23}}{{1000}} = - 0,023;\,\,\frac{{88}}{{100}} = 0,88\end{array}\).
98/25 = 3,92
36/16 = 2,25
18/4 = 4,5
26/5 = 5,2
k mình nhoa ! ~~~
\(\begin{array}{l}a)0,36.\frac{{ - 5}}{9}\\ = \frac{{36}}{{100}}.\frac{{ - 5}}{9}\\ = \frac{9}{{25}}.\frac{{ - 5}}{9}\\ = \frac{{ - 1}}{5}\\b)\frac{{ - 7}}{6}:1\frac{5}{7}\\ = \frac{{ - 7}}{6}:\frac{{12}}{7}\\ = \frac{{ - 7}}{6}.\frac{7}{{12}}\\ = \frac{{ - 49}}{{72}}\end{array}\)
Chú ý: Khi tính toán, nếu phân số chưa ở dạng tối giản thì ta nên rút gọn về dạng tối giản để tính toán thuận tiện hơn.
\(\frac{23}{5}\)\(=\)\(4\frac{3}{10}\);\(\frac{67}{10}\)\(=\)\(6\frac{7}{10}\);\(\frac{313}{100}\)\(=\)\(3\frac{13}{100}\); \(\frac{168}{11}\)= \(11\frac{68}{100}\)
mk nha
-124/-2017;0;-24/35;-19/30;-5/9;-25/47;23/-49
tk mk nha, mk đg bị âm điểm
2/5=0,4
3/25=0.12
98/125=0.784
3/4=0,75
1/2=0,5
HT~~~
TL :
a) \(\frac{2}{5}\)= 0,4
b) \(\frac{3}{25}\)= 0,75
c) \(\frac{98}{125}\)= 0,784
d) \(\frac{3}{4}\)= 0,75
e) \(\frac{1}{2}\)= 0,5
a) \(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)
\(=\frac{31}{23}-\frac{15}{23}\)
\(=\frac{16}{23}\)
b) \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{-67}{67}+\frac{41}{41}\)
\(=\frac{1}{3}-1+1\)
\(=\frac{1}{3}\)
c) \(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{52}-\frac{3}{11}\right)\)
\(=\frac{38}{45}-\frac{8}{45}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{30}{45}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{2}{3}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{104+51}{156}+\frac{3}{11}\)
\(=\frac{155}{156}+\frac{3}{11}\)
\(=\frac{156}{156}-\frac{1}{156}+\frac{3}{11}\)
\(=1-\frac{1}{156}+\frac{3}{11}\)
\(=1-\left(\frac{11-468}{1716}\right)\)
\(=1-\frac{-457}{1716}\)
\(=1+\frac{457}{1716}\)
\(=\frac{2173}{1716}\)
a)31/23-(7/32+8/23)=31/23-7/32-8/23=(31/23-8/23)-7/32=1-7/32=25/32