500 - {5[409 - (23 . 3 - 21)2 + 103 ]} : 15
67 - [8 + 7 . 32 - 24 : 6 + (9 - 7)2] : 15
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a)58(-45+-24)+-69.42
=58.(-69)+(-69).42
=-69.(58+42)
=-69.100
=-6900
a;
A= 58.(-45) + (-58).24 + (-69).42
A = -58.(45 + 24) - 69.42
A =-58.69 - 69.42
A = -69.(58 + 42)
A = -69.100
A = -6900
b; 139 - (-65 + 239) - (85 + 120)
B = 139 + 65 - 239 - 85 - 120
B = -(239 - 139) - (85 - 65) - 120
B = - 100 - 20 - 120
B = - 120 - 120
B = - 240
ℓ. 500 – {5[409 – (2³.3 – 21)²] + 10³} : 15
= 500 - {5[409-(8.3-21)2]+103}:15
= 500-{5[409-(24-21)2]+1000}:15
= 500-{5[409-32]+1000}:15
= 500-{5[409-9]+1000}:15
= 500-{[5.400]+1000}:15
= 500-{2000+1000}:15
= 500-3000:15
= 500-200
= 300
m. 67 – [8 + 7.3² – 24 : 6 + (9 – 7)³] : 15
= 67 – [8 + 7.9 – 4 + 23] : 15
= 67 – [8 + 63 – 4 + 8] : 15
= 67 – [71 – 4 + 8] : 15
= 67 – [67 + 8] : 15
= 67 – 75 : 15
= 67 – 5
= 62
n. (–23) + 13 + (–17) + 57
= (–10) + [(–17) + 57]
= (–10) + 40
= 30
o. (–123) + |–13| + (–7)
= [(–123) + (–7)] + |–13|
= (–130) + 13
= (–117)
p. |–10| + |45| + (–|–455|) + |–750|
= 10 + 45 + (–455) + 750
= (10 + 45 + 750) + (–455)
= 805 + (–455)
= 350
q. –|–33| + (–15) + 20 – |45 – 40| – 57 = (–33) + (–15) + 20 – |5| – 57 = (–48) + (20 + 5 + 57) = (–48) + 82 = 34 h. 9.|40 – 37| – |2.13 – 52| = 9.|3| – |26 – 52| = 9.3 – |–26| = 27 – 26 = 1500 - {5.[409.(23.3 - 21)2] + 103 } : 15
= 500 - { 5. [409.(8.3 - 21)2 ] + 1000} : 15
= 500 - {5. [409.(24 - 21)2 ] + 1000} : 15
= 500 - {5. [409.32 ] + 1000} : 15
= 500 - {5. [409.9] + 1000} : 15
= 500 - {5. 3681 + 1000} : 15
= 500 - {18405 + 1000} : 15
= 500 - 19405 : 15
= 500 - 1293,66666666....
= Không có số thỏa mãn đề bài.
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
101 - {36 + [7 . 32 - 24 : 3 + ( 9 - 7)3 ]} : 32
= 101 - [36 + (7 . 9 - 24 : 3 + 23)] : 9
= 101 - [36 + (63 - 8 + 8)] : 9
= 101 - (36 + 63) : 9
= 101 - 99 : 9
= 101 - 11 = 90
trả lời :
101 - {36 + [7 . 32 - 24 : 3 + ( 9 - 7)3 ]} : 32
= 101 - [36 + (7 . 9 - 24 : 3 + 23)] : 9
= 101 - [36 + (63 - 8 + 8)] : 9
= 101 - (36 + 63) : 9
= 101 - 99 : 9
= 101 - 11 = 90
) 2 x 6 = 12 3 x 7 = 21
12 : 2 = 6 21 : 3 = 7
12 : 6 = 2 21 : 7 = 3
4 x 8 = 32 5 x 9 = 45
32 : 4 = 8 45 : 5 = 9
32 : 8 = 4 45 : 9 = 5
b) 600 : 3 = 200 800 : 4 = 200 400 : 2 = 200
600 : 2 = 300 800 : 2 = 400 500 : 5 = 100
a) 2x6=12 3x7=21
12:2=6 21:3=7
12:6=2 21:7=3
4x8=32 5x9=45
32:4=8 45:5=9
32:8=4 45:9=5
b) 600:3=200 800:4=200 400:2=200
600:2=300 800:2=400 500:5=100
A Legend Never Dies
\(500-\left\{5\left[409-\left(2^3\cdot3-21\right)^2+10^3\right]\right\}:15\)
\(=500-\left\{5\left[409-9+1000\right]\right\}:15\)
\(=500-\left\{5\cdot1400\right\}:15\)
\(=500-7000:15\)
\(=500-\dfrac{1400}{3}\)
\(=\dfrac{100}{3}\)
\(67-\left[8+7\cdot3^2-24:6+\left(9-7\right)^2\right]:15\)
\(=67-\left[8+7\cdot9-24:6+4\right]:15\)
\(=67-\left[8+63-4+4\right]:15\)
\(=67-71:15\)
\(=67-\dfrac{71}{15}\)
\(=\dfrac{934}{15}\)
\(PeaGea\)