Bài 1.
a) Tìm x biết: (x + 1)3 - (x + 3)2.(x + 1) + 4x2 = -12
b) C/m giá trị biểu thức sau không phụ thuộc vào biến: (x + 2).(x - 5) + 3.(x - 4).(x + 4) - (3x - 1/2)2 + 5x2
Bài 2.
a) Tính nhẩm: 542 + 462 + 92.54
b) Cho: x2 + x + 1 = a
Tính M= x4 + 2x3 + 5x2 + 4x + 4 theo a
SORY I'M IN GRADE 6
bài 1:
a,\(\left(x+1\right)^3-\left(x+3\right)^2\cdot\left(x+1\right)+4x^2=\)-12
\(\Rightarrow\left(x+1\right)\cdot[\left(x+1\right)^2-\left(x+3\right)^2]+4x^2=-12\)
\(\Rightarrow\left(x+1\right)\cdot[\left(x+1+x+3\right)\cdot\left(x+1-x-3\right)]+4x^2=-12\)
\(\Rightarrow\left(x+1\right)\cdot\left(2x+4\right)\cdot\left(-2\right)+4x^2=-4\cdot3\)
\(\Rightarrow\left(x+1\right)\cdot2\cdot\left(x+2\right)\cdot\left(-2\right)+4x^2=-4\cdot3\)
\(\Rightarrow\left(x+1\right)\cdot\left(x+2\right)\cdot\left(-4\right)+4x^2=-4\cdot3\)
\(\Rightarrow\left(x+1\right)\cdot\left(x+2\right)-x^2=3\)
\(\Rightarrow x^2+2x+x+2-x^2=3\)
\(\Rightarrow3x=1\Rightarrow x=\frac{1}{3}\)