Question

[Hoang Hong Thuy]

Tìm x, y biết: 6xy - 2x + 9y = 68

Answer 1

[Mei Shine]

Ta có: \(6xy-2x+9y=68\)

\(\Leftrightarrow2x\left(3y-1\right)+3\left(3y-1\right)=65\)

\(\Leftrightarrow\left(3y-1\right)\left(2x+3\right)=65\)

\(\Rightarrow\left(2x+3\right);\left(3y-1\right)\inƯ\left(65\right)=\left\{\pm1,\pm5,\pm13,\pm65\right\}\)

Ta có bảng sau:

2x+3	1	-1	5	-5	13	-13	65	-65
3y-1	65	-65	13	-13	5	-5	1	-1
x	-1	-2	1	-4	5	-8	31	-34
y	22	-64/3	14/3	-4	2	-4/3	2/3	0

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