12-3x[39-(5-2^2)]
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a, 2 x ( 15 - 3x ) = 12
=> 15 - 3x = 6
=> 3x = 9
=> x = 3
b, 39 - 2 x ( 31 - 3x ) = 15
=> 2 x ( 31 - 3x ) = 24
=> 31 - 3x = 12
=> 3x = 19
=> x = \(\frac{19}{3}\)
nếu mk sửa đề có sai thì nhờ bạn sửa đề lại giúp mk nha
\(=3^{x+1}\left(1+3+3^2\right)+...+3^{x+10}\left(1+3+3^2\right)=\)
\(=3^x.3.13+...+3^{x+9}.3.13=\)
\(39\left(3^x+...+3^{x+9}\right)⋮39\)
b ) 5x + x = 39 - 32
=> 6x = 39 - 9
6x = 30
x = 30 : 6
x = 5
a ) 5x + 3x = 36 : 32 . 4 + 12
=> 8x = 36-2 . 4 + 12
8x = 34 . 4 + 12
8x = 81 . 4 + 12
8x = 324 + 12
8x = 336
x = 336 : 8
x = 42
k nha !
1) 8x = 81 x 4 + 12
8x = 324 + 12
8x = 336
x = 336 : 8
x = 42
2) 6x = 30
x = 30 : 6
x = 5
nha ^^
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
bạn làm sai rồi !
\(\Leftrightarrow x\left(3x+2\right)+\left(x+1\right)^2-\left(2x-5\right)\left(2x+5\right)=-12\)
\(\Leftrightarrow3x^2+2x+x^2+2x+1-4x^2+25=-12\)
\(\Leftrightarrow4x+26=-12\)
\(\Leftrightarrow4x=-38\)
\(\Leftrightarrow x=-\frac{19}{2}\)
Vậy tập nghiệm của phương trình là \(S=\left\{-\frac{19}{2}\right\}\)
\(12-3.\left[39-\left(5-2^2\right)\right]\)
\(=12-3.\left[39-\left(5-4\right)\right]\)
\(=12-3\left[39-1\right]\)
\(=12-3.38\)
\(=12-114=-102\)
12 - 3. [39 - (5 - 22)]
= 12 - 3. [39 - (5 - 4)]
= 12 - 3. [39 - 1]
= 12 - 3.38
= 12 - 114
= -102