-5/32-17/8
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a) 16-x=21+8
16-x=29
x=16-29
x=-13
b)x - 32= - 22
x = - 22 +32
x = 10
a) \(\text{16 - x = 21 - (-8).}\)
<=> \(\text{16 - x = 29.}\)
<=> \(x=-13.\)
Vậy \(x=-13.\)
b) \(\text{x - 32 = (-5) - 17}.\)
<=> \(\text{x - 32 = -22}.\)
<=> \(x=10.\)
Vậy \(x=10.\)
a) (135 - 35) . (-37) + 37 . (-42 - 58)
= 100 . 0 . (-100)
= 0
b) -65 . (87 - 17) - 87 . (17 - 65)
= -65 . 70 - 87 . (-48)
= -4550 - 135
= -4415
a) 17 - 25 + 55 - 17 = (17 - 17) + (55-25)= 0 + 20 = 30
b) 25 - (-75) + 32 - (32 + 75) = 25 + 75 +32 - 32 - 75 = 25 + (75-75)+(32-32) = 25
c) (-5).8.(-2).3= 10.24=240
d) (-15)+(-122)= -137
e) -18.(5 - 6) = -18 .(-1)= 18.
BYE :3
d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)
\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)
hay \(x=\dfrac{25}{372}\)
Vậy: \(x=\dfrac{25}{372}\)
e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)
f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)
\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)
\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)
\(\Leftrightarrow3x=\dfrac{1}{9}\)
hay \(x=\dfrac{1}{27}\)
g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)
\(\Leftrightarrow\dfrac{4}{3}x=2\)
hay \(x=\dfrac{3}{2}\)
Vậy: \(x=\dfrac{3}{2}\)
h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)
Vậy ...
i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)
Vậy ...
a) 47 + 18 – 26 = 39
b) 3 × 8 : 4 = 24 : 4 = 6
c) 5 × 8 – 32 = 40 – 32 = 8
d) 36 : 4 + 17 = 9 + 17 = 26
(-35)+|-12+(-5)|+(-41)=-35+17-41=-59
(-27)+|17-8|+(+32)=-27+9+32=14
giải bài toán: cho tam giác MNP, NTlà phân giác của góc N biết MN=4cm, NT=10cm, MP=8cm:TínhTM, TP?
- \(\dfrac{5}{32}\) - \(\dfrac{17}{8}\)
= - (\(\dfrac{5}{32}\) + \(\dfrac{68}{32}\))
= - \(\dfrac{73}{32}\)