A) (2/5:2/3+6).3-18 B) 25.(-37)+25.-63
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b) 25.(37+5) -63.(-25)+5.(-125)
= 25.42+63.25+5.25.(-5)
= 25.[42+25+5.(-5)]
= 25.[42+25-25]
= 25.42
=1050
c) 31 . (-18)+ 31.(-81)-31
= 31.(-18)+31.(-81)+31.(-1)
= 31.[-18+(-81)+(-1)]
= 31.(-100)
= -3100
A = 136 . 25 + 75 . 136 - 62 . 102 B = 90 - (22 . 25 - 32 . 7) C = 720 - {96 . [ (24 . 2 - 5) : 32 . 130] }
= 136 . (25 + 75) - 36 . 100 = 90 - (4 . 25 - 9 . 7)
= 136 . 100 - 36 . 100 = 90 - (100 - 63)
= (136 - 36) . 100 = 90 - 37
= 100 . 100 = 53
= 10000
D = 570 + {96 . [ (24 . 2 - 5) : 32 . 130] } E = 37 . 24 + 37 . 76 + 63 . 79 + 21 . 63
= 570 + {96 . [ (16 . 2 - 5) : 9 . 1] } = 37 . (24 + 76) + 63 . (79 + 21)
= 570 + [96 . (27 : 9) ] = 37 . 100 + 63 . 100
= 570 + (96 . 3) = (37 + 63) . 100
= 570 + 288 = 100 . 100
= 858 = 10000
a,(567-46)-(54+567)
=567-46+54-567
=567.(46+54)
=567.100
=56700
a) \(...=16.\left(36-37\right)=16.\left(-1\right)=-16\)
b) \(...=9.3+9.50=9.\left(3+50\right)=9.53=477\)
c) \(...=2.\left(\left(5.16-18\right)+36:18\right)=2.\left(70+2\right)=2.72=144\)
d) \(...=5\left(48:8+44\right)=5\left(6+44\right)=5.50=250\)
e) \(...=20-6=14\)
f) \(...=50+13-2=61\)
a) 16 . 36 - 16 . 37
= 16 . (36 - 37)
= 16 . (-1)
= -16
b) 36 : 4 . 3 + 9 . 50
= 9 . 3 + 9 . 50
= 9 . (3 + 50)
= 9 . 53
= 477
c) 2 . (5 . 16 - 18) + 36 : 18 . 2
= 2 . (80 - 18) + 2 . 2
= 2 . 62 + 2 . 2
= 2 . (62 + 2)
= 2 . 64
= 128
Ta có: \(6^2\cdot37+12\cdot38\cdot3+18\cdot25\cdot2\)
\(=36\cdot37+36\cdot38+36\cdot25\)
\(=36\left(37+38+25\right)\)
\(=36\cdot100=3600\)
a: \(\left(\dfrac{2}{5}:\dfrac{2}{3}+6\right)\cdot3-18\)
\(=\left(\dfrac{2}{5}\cdot\dfrac{3}{2}+6\right)\cdot3-18\)
\(=\left(\dfrac{3}{5}+6\right)\cdot3-18\)
\(=\dfrac{9}{5}+18-18=\dfrac{9}{5}\)
b: \(25\cdot\left(-37\right)+25\cdot\left(-63\right)\)
\(=25\left(-37-63\right)\)
\(=25\cdot\left(-100\right)=-2500\)