d)-37.(-19)+37.(-19)
e)(29-9).(-9)+(-13-7).21
h)12.(-47)+12.(-19)+(-66).88
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nhiều quá mk phụ bạn chút thôi
a)47*(23+50)-23*(47+50)=47*23+47*50-23*47+23*50=(47*23-23*47)+(47*50+23*50)=(47+23)*50=70*50=3500
b)29*(85-47)+85*(47-29)=29*85-29*47+85*47-85*29=(29*85-85*29)+(85*47-29*47)=(85-29)*47=56*47=2632
c)37*90-37*(-10)=37*[90-(-10)]=37*100=3700
a. 47.[23+50]-23.[47+50]
=47.73-23.97
=3431-2231
=1200
b,29.[85-47]+85.[47-29]
=29.38+85.18
=1102+1520
=-428
c,37.90-37.[-10]
=37.(90-(-10))
=37.100
=3700
d,15.12-3.5.10
=15.12-15.10
=15.(12-10)
=15.2
=30
e,29.[19-13]-19.[29-13]
=29.6-19.16
=174-304
=-130
f,33.[17-5]-17.[33-5]
=33.12-17.32
=396-544
=-148
g,54-6.[17+9]
=54-6.26
=54-156
=-102
h,1000+[-570]+2341+[-430]
=430+2341+(-430)
=(-430+430)+2341
=0+2341
=2341
a. \(\left(-37\right)+14+26+37\)
\(=\left[\left(-37\right)+37\right]+\left(14+26\right)\)
\(=0+40\)
\(=40\)
b. \(\left(-24\right)+6+10+24\)
\(=\left[\left(-24\right)+24\right]+6+10\)
\(=0+6+10\)
\(=16\)
c. \(15+23+\left(-25\right)+\left(-23\right)\)
\(=\left[\left(-25\right)+15\right]+\left[\left(-23\right)+23\right]\)
\(=-10+0\)
\(=-10\)
các câu khác bn tự lm
\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
Em nến gõ bằng công thức toán học em nhé. Như vậy mọi người nới hiểu đúng đề bài để trợ giúp cho em một cách tốt nhất em ạ!
a) \(\dfrac{25}{37}\times\dfrac{18}{29}+\dfrac{18}{29}\times\dfrac{12}{37}\)
\(=\dfrac{18}{29}\times\left(\dfrac{25}{37}+\dfrac{12}{37}\right)\)
\(=\dfrac{18}{29}\times\dfrac{37}{37}\)
\(=\dfrac{18}{29}\times1\)
\(=\dfrac{18}{29}\)
b) \(\dfrac{31}{85}\times\dfrac{11}{19}+\dfrac{31}{85}\times\dfrac{12}{19}-\dfrac{42}{19}\times\dfrac{31}{85}\)
\(=\dfrac{31}{85}\times\left(\dfrac{11}{19}+\dfrac{12}{19}-\dfrac{42}{19}\right)\)
\(=\dfrac{31}{85}\times\dfrac{-19}{19}\)
\(=\dfrac{31}{85}\times-1\)
\(=-\dfrac{31}{85}\)
c) \(\dfrac{16}{53}:\dfrac{17}{9}-\dfrac{16}{53}:\dfrac{17}{8}\)
\(=\dfrac{16}{53}:\left(\dfrac{9}{17}-\dfrac{8}{17}\right)\)
\(=\dfrac{16}{53}:\dfrac{1}{17}\)
\(=\dfrac{16}{901}\)
c) \(\dfrac{1}{5}\times\dfrac{12}{31}\times\dfrac{4}{3}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\dfrac{12}{31}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\left(\dfrac{12}{31}+\dfrac{19}{31}\right)\)
\(=\dfrac{4}{15}\times\dfrac{31}{31}\)
\(=\dfrac{4}{15}\times1\)
\(=\dfrac{4}{15}\)
a: =18/29*(25/37+12/37)
=18/29
b: =31/85(11/19+12/19-42/19)
=-31/85
c; =16/53(9/17+8/17)=16/53
d: =4/15(12/31+19/31)=4/15
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50=1275
d: \(-37\cdot\left(-19\right)+37\left(-19\right)\)
\(=-19\left(-37+37\right)\)
\(=-19\cdot0=0\)
e: \(\left(29-9\right)\cdot\left(-9\right)+\left(-13-7\right)\cdot21\)
\(=20\cdot\left(-9\right)+\left(-20\right)\cdot21\)
\(=-20\left(9+21\right)\)
\(=-20\cdot30=-600\)
h: \(12\cdot\left(-47\right)+12\left(-19\right)+\left(-66\right)\cdot88\)
\(=12\left(-47-19\right)+\left(-66\right)\cdot88\)
\(=\left(-66\right)\cdot12+\left(-66\right)\cdot88\)
\(=-66\left(12+88\right)\)
\(=-66\cdot100=-6600\)